AWK - 将一个变量拆分成一个索引而没有循环的数组

Question

我在变量ArtTEXT中有这个（演示）文本。

1|Reporting Problems and Bugs. 
2|Other freely available awk implementations. 
5|Summary of installation. 
8|How to disable certain gawk extensions. 
3|Making Additions To gawk. 
7|Accessing the Git repository. 

这是一个变量，其中行用已知字符串分隔。

我想将它分成一个数组，其中行首的数字将是使用一个命令的数组行的索引，而不循环行。

结果应该是：

arr[1] => Reporting Problems and Bugs. 
arr[2] => Other freely available awk implementations. 
arr[5] => Summary of installation. 
arr[8] => How to disable certain gawk extensions. 
arr[3] => Making Additions To gawk. 
arr[7] => Accessing the Git repository. 

这可能吗？

Answer 1

不需要使用数组，因为您只需更改字段分隔符即可。

awk 'BEGIN{FS="|"}{print $1, $2}' input.txt 

$ 0包含全线 $ 1包含索引 $ 2句

Answer 2

不，这是不可能的。以下是如何从变量，只要你想填充数组（假设分隔行“已知串”是一个换行符）：

$ awk -v ArtTEXT='1|Reporting Problems and Bugs. 
2|Other freely available awk implementations. 
5|Summary of installation. 
8|How to disable certain gawk extensions. 
3|Making Additions To gawk. 
7|Accessing the Git repository.' ' 
BEGIN { 
    split(ArtTEXT,lines,/\n/) 
    for (lineNr in lines) { 
     split(lines[lineNr],flds,/\|/) 
     arr[flds[1]] = flds[2] 
    } 

    for (i in arr) { 
     printf "arr[%d] => %s\n", i, arr[i] 
    } 
} 
' 
arr[1] => Reporting Problems and Bugs. 
arr[2] => Other freely available awk implementations. 
arr[3] => Making Additions To gawk. 
arr[5] => Summary of installation. 
arr[7] => Accessing the Git repository. 
arr[8] => How to disable certain gawk extensions. 

Answer 3

如果记录分隔符是换行，你可以重复使用引号扩张的变量，使用awk像往常一样，如

echo "$ArtTEXT" | awk -F"|" '{ix[NR]=$1;arr[$1]=$2} END{for(i=1;i<=NR;i++) print "arr[" ix[i] "] => " arr[ix[i]]}' 

arr[1] => Reporting Problems and Bugs. 
arr[2] => Other freely available awk implementations. 
arr[5] => Summary of installation. 
arr[8] => How to disable certain gawk extensions. 
arr[3] => Making Additions To gawk. 
arr[7] => Accessing the Git repository. 

由于awk数组不保存，你需要保持一个单独的索引的顺序。