操作时间限制

Question

是有办法的时间限制oparations在python，如：

try: 
    cmds.file(file, o=1, pmt=0) 
except: 
    print "Sorry, run out of time" 
    pass 

Answer 1

如果你在Mac或基于Unix的系统，你可以使用signal.SIGALRM强制超时函数需要太长时间，所以你的代码看起来像：

import signal 

class TimeoutException(Exception): # custom exception 
    pass 

def timeout_handler(signum, frame): # raises exception when signal sent 
    raise TimeoutException 

# Makes it so that when SIGALRM signal sent, it calls the function timeout_handler, which raises your exception 
signal.signal(signal.SIGALRM, timeout_handler) 

# Start the timer. Once 5 seconds are over, a SIGALRM signal is sent. 
signal.alarm(5) 
try: 
    cmds.file(file, o=1, pmt=0) 
except TimeoutException: 
    print "Sorry, run out of time" # you don't need pass because that's in the exception definition 

基本上，你在创建后的时间限制为最多（即SIGALRM发送）当这样提出了一个自定义异常。你当然可以调整时间限制。