2016-11-10 136 views
2

字母顺序我有几个特征向量是这样的:检测的特征向量

lastname <- c("Smith" ,"Johnson" , "Williams" , "Moore" , "Taylor", "Jones" 
, "Brown" , "Davis" , "Miller" , "Wilson") 

姓氏的最后4个元素是按字母顺序排列。 我想分割字母顺序开始的向量。 因此,其结果会是什么样子:

lastname1 <- c("Smith" ,"Johnson" , "Williams" , "Moore" , "Taylor", "Jones") 
lastname2 <- c("Brown" , "Davis" , "Miller" , "Wilson") 

按字母顺序排列的部分总是位于结束,但它的长度可能会有所不同。

任何帮助非常感谢!

回答

2

我们可以创建一个逻辑索引,然后split向量由索引创建listvector s。

i1 <- rev(cumsum(c(TRUE, diff(rank(rev(lastname))) >0))==1) 
split(lastname, i1) 
#$`FALSE` 
#[1] "Smith" "Johnson" "Williams" "Moore" "Taylor" "Jones" 

#$`TRUE` 
#[1] "Brown" "Davis" "Miller" "Wilson" 
0

这也将工作:

pos <- tail(which(sapply(1:(length(lastname)-1), function(i) lastname[i] < lastname[i+1])==FALSE),1) 
lastname[1:pos] 
# [1] "Smith" "Johnson" "Williams" "Moore" "Taylor" "Jones" 
lastname[(pos+1):length(lastname)] 
# [1] "Brown" "Davis" "Miller" "Wilson"