我试图使用PropertyListDecoder()
来解码plist,但是当我试图访问密钥时,出现一个错误,指出它的格式不正确。我对我做错的事情感到不知所措。我假设我可以解码一个Plist
文件的方式,我可以解码一个JSON文件的权利?我不知道,我还是这个新手。解码PropertyList使用Swift 4 Codable PropertyListDecoder()
//struct for PLists
struct AccessControl: Decodable {
enum AccessControlKeys: String, CodingKey {
case api
}
enum KeySecretKeys: String, CodingKey {
case apiKey = "KEY"
case apiSecret = "SECRET"
}
var KEYS: [KeySecrets]
//custom decoder
init(from decoder: Decoder) throws {
let accessContainer = try decoder.container(keyedBy: AccessControlKeys.self)
let nestedContainer = try accessContainer.nestedContainer(keyedBy: KeySecretKeys.self, forKey: .api)
self.KEYS = try nestedContainer([KeySecrets].self, forKey: .apiKey)
self.KEYS = try nestedContainer.decode([KeySecrets].self, forKey: .apiSecret)
}
}
struct KeySecrets: Decodable {
var apiKey: String
var apiSecret: String
}
func provideAccessKeys(for api: apis = .api, mode: modes = .dev) -> keysForApi? {
switch api {
case .api:
print("Api")
}
switch mode {
case .dev:
print("mode - developers")
case .test:
print("mode - test")
case .prod:
print("mode - production")
}
}
这是我在这第一种方法,但它会抛出一个错误说
“中的数据无法读取,因为它是格式不正确”
if let fileURL = Bundle.main.url(forResource: "Accesscontrol", withExtension: "plist") {
do {
let data = try Data.init(contentsOf: fileURL, options: .mappedIfSafe)
let decoder = PropertyListDecoder()
let result = try decoder.decode(AccessControl.self, from: data)
} catch {
print(error.localizedDescription)
}
}
第二种方法,刚刚放弃了Codable
所有在一起,仍然不能拉出数值
guard let fileUrl = Bundle.main.url(forResource: "Accesscontrol", withExtension: "plist") else {return}
let key: String
let secret: String
do {
let data = try Data.init(contentsOf: fileUrl, options: .mappedIfSafe)
let plist = try! PropertyListSerialization.propertyList(from:data, options: [], format: nil) as! [Any]
print(plist)
let dictionary = plist[api.rawValue]
} catch {
print(error.localizedDescription)
}
plist文件的结构类似于
<plist version="1.0">
<dict>
<key>A_GROUP_OF_KEYS</key>
<array>
<dict>
<key>KEY1</key>
<string>KEY1_STRING</string>
<key>SECRET1_KEY</key>
<string>SECRET1_STRING</string>
</dict>
<dict>
<key>KEY2</key>
<string>KEY2_STRING</string>
<key>SECRET2_KEY</key>
<string>SECRET2_VALUE</string>
</dict>
<dict>
<key>KEY</key>
<string>KEY_STRING</string>
<key>SECRET_KEY</key>
<string>SECRET_VALUE</string>
</dict>
</array>
<key>ANOTHER_GROUP_OF_KEYS</key>
<array>
<dict>
<key>KEY1</key>
<string>KEY1_STRING</string>
<key>SECRET1_KEY</key>
<string>SECRET1_STRING</string>
</dict>
<dict>
<key>KEY2</key>
<string>KEY2_STRING</string>
<key>SECRET2_KEY</key>
<string>SECRET2_VALUE</string>
</dict>
<dict>
<key>KEY</key>
<string>KEY_STRING</string>
<key>SECRET_KEY</key>
<string>SECRET_VALUE</string>
</dict>
</array>
</dict>
</plist>
有什么建议?
我不知道这是否是在plist中或你错过了关闭字典在这里,而粘贴 –
这不是一个有效的plist。你可以编辑它吗?当事情到处都很难得到plist文件的结构。另外,添加你的'AccessControl'类的定义/ struct –
我更新了这篇文章。 – SirCJ