我想解析一个大的JSON字符串,我从URL中检索。我使用的测试JSON低于:在Swift中使用Decodable和CodingKeys解析JSON 4
let json = """
{
"feed": {
"title": "Harry Potter",
"test": "I dont want this value",
"results": [
{
"author": "JK Rowling",
"artworkURL": "A url",
"genres": [
{
"name": "Fantasy"
},
{
"name": "Scifi"
}
],
"name": "Goblet of Fire",
"releaseDate": "2000-07-08"
},
{
"author": "JK Rowling",
"artworkURL": "A url",
"genres": [
{
"name": "Fantasy"
},
{
"name": "Scifi"
}
],
"name": "Half Blood Prince",
"releaseDate": "2009-07-15"
}
]
}
}
""".data(using: .utf8)!
我有几个数据结构的数据放置到:
struct Genre: Decodable {
let name: String
}
struct Book: Decodable {
let author: String
let artworkURL: URL
let genres: [Genre]
let name: String
let releaseDate: String
}
struct BookCollection {
let title: String
let books: [Book]
enum CodingKeys: String, CodingKey {
case feed
}
enum FeedKeys: String, CodingKey {
case title, results
}
enum ResultKeys: String, CodingKey {
case author, artworkURL, genres, name, releaseDate
}
enum GenreKeys: String, CodingKey {
case name
}
}
extension BookCollection: Decodable {
init(from decoder: Decoder) throws {
let values = try decoder.container(keyedBy: CodingKeys.self)
let feed = try values.nestedContainer(keyedBy: FeedKeys.self,
forKey: .feed)
self.title = try feed.decode(String.self, forKey: .title)
self.books = try feed.decode([Track].self, forKey: .results)
}
}
我然后打印过的资料,像这样:
do {
let response = try JSONDecoder().decode(BookCollection.self, from: json)
for book in response.books {
print(book.genres)
}
} catch {
print(error)
}
它成功地打印除流派外的所有信息。这给我一个流派,但我不能做 book.genres.name
访问名称。我必须使用: book.genres[0]
它给我的结果只是第一个索引。
有没有一种方法可以在我的BookCollection
扩展中完善我的JSON解码,然后利用book.genres.name
?
谢谢
要清楚,'book.genres.name'应该返回什么值? –
@PauloMattos它应该为每本书返回一个数组。第一本书是“幻想”和“科幻”。 –
@DominicPilla你可以添加一个只读的计算属性到你的Book结构'扩展书籍'var allGenres:[String] { return genres.map {$ 0.name} } }'并使用print(book.allGenres )' –