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规则三。复制构造函数,赋值运算符执行法则三。复制构造函数,赋值运算符实现
#include <iostream>
using namespace std;
class IntPart
{
public:
IntPart(); // default constructor
IntPart(int n);
private:
unsigned int* Counts;
unsigned int numParts;
unsigned int size;
};
IntPart::IntPart()
{
Counts = new int[101](); // allocate all to 0s
numParts = 0;
}
IntPart::IntPart(int n)
{
Counts = new int[n+1](); // allocate all to 0s
Counts[n] = 1;
numParts = 1;
}
int main()
{
IntPart ip2(200);
IntPart ip3(100);
IntPart ip(ip2); // call default and copy constructor?
IntPart ip4; // call default constructor
ip4 = ip3;
system("pause"); return 0;
}
很明显,这需要有三条规则。 你能帮我定义他们吗?
Q0。
IntPart ip(ip2);
这是否一个科瑞IP对象调用默认的构造函数 ,之后,调用拷贝构造函数? 我对不对?
Q1。定义析构函数。
IntPart::~IntPart()
{ delete [] Counts; }
它正确吗? Q2302。定义复制构造函数。
IntPart::IntPart(const IntPart& a)
{ // how do I do this? I need to find the length... size.... could anybody can do this?
}
Q3。定义赋值运算符。
IntPart& IntPart::operator= (const IntPart& a)
{
if (right != a)
{
// Anybody has any idea about how to implement this?
}
return *this;
}
谢谢, 我将不胜感激!
字面上有数百万*样本对象实现遵循网络上的三规则。数千在这个站点单独。看到右边的“相关”列表?尝试点击它。 VTC。 – WhozCraig 2013-04-23 06:39:21
如果需要可能为'Counts'分配空间,并从'a.Counts'复制。可能首先删除旧的“Counts”(如果它太小)。 – 2013-04-23 06:42:01
可能重复[三条法则是什么?](http://stackoverflow.com/questions/4172722/what-is-the-rule-of-ree) – 2013-04-23 07:23:51