我遇到了MySQL LIKE未返回所有可能结果的问题。我有下面的代码:查询没有返回所有可能的结果
<?php
$query = "SELECT `user_id`,
`rank`,
`habbo_name`,
`rating`,
`branch`
FROM `personnel`
WHERE status='active' AND
rating='(DIROPS)'
ORDER BY `habbo_name`";
$result = $con->prepare($query);
$result->execute();
while ($row = $result->fetch())
{
echo "<b>DIROPS:</b> " . htmlspecialchars($row['habbo_name']) . "<br>";
}
$query = "SELECT `user_id`,
`rank`,
`habbo_name`,
`rating`,
`branch`
FROM `personnel`
WHERE status='active' AND
rating='(CO TECOM)' AND
`branch`='usmc'
ORDER BY `habbo_name`";
$result = $con->prepare($query);
$result->execute();
while ($row = $result->fetch())
{
echo "<b>CO TECOM:</b> " . htmlspecialchars($row['habbo_name']) . "<br>";
}
$query = "SELECT `user_id`,
`rank`,
`habbo_name`,
`rating`,
`branch`
FROM `personnel`
WHERE status='active' AND
rating='(XO TECOM)' AND
`branch`='usmc'
ORDER BY `habbo_name`";
$result = $con->prepare($query);
$result->execute();
while ($row = $result->fetch())
{
echo "<b>XO TECOM:</b> " . htmlspecialchars($row['habbo_name']) . "<br>";
}
?>
<br>
<?php
$query = "SELECT `user_id`,
`rank`,
`habbo_name`,
`rating`,
`branch`
FROM `personnel`
WHERE status='active' AND
`rating` LIKE '%(TECOM%' OR
`rating` LIKE '%/TECOM%' AND
status='active'
ORDER BY `habbo_name`";
$result = $con->prepare($query);
$result->execute();
while ($row = $result->fetch())
{
echo "<b>TECOM:</b> " . htmlspecialchars($row['habbo_name']) . "<br>";
}
?>
这一点,因为据我所知,应该打印出来谁拥有等级设置为(DIROPS)的人,(CO TECOM),(XO TECOM),然后(TECOM或/ TECOM)。
我的问题是只有DIROPS和其他几个正在返回。这是结果我从代码获得:
任何人都可以让我知道我错了?谢谢!
编辑:记录应当显示: -
TEO-emo12 (DIROPS) RockerManiac123 (CO TECOM) Rach-L (Lugn) (XO TECOM) Reyess (TECOM) zachary1142 (AuXHiDef-) (TECOM) norsk.no (TECOM) lordoftjefly (mingrana) (PPO/TECOM) spen1000 (TECOM/DI)
编辑:添加记录它应该显示 – user2547576
你需要这么多的查询吗?不会有人这样做吗? – Strawberry
性能不是问题,我是一个新手,所以我更容易将它分解为单独的查询。更不用说他们在“评级”列中搜索不同的东西,然后用不同的前缀回显出来。 – user2547576