检查给定日期是否适合日期范围

Question

如果我在表格中有两个日期列，startDate和endDate。如何返回给定日期适合这两个日期之间的行？例如：

如果日期是2012-10-25

应该返回如下行

startDate - endDate 
2012-10-25 - 2012-10-25 
2011-09-10 - 2013-11-15 
2012-10-20 - 2012-10-25 
2012-10-23 - 2012-10-28 
2012-09-14 - 2012-10-28 

从以下行：

startDate - endDate 
2012-10-25 - 2012-10-25 
2011-09-10 - 2013-11-15 
2012-01-11 - 2012-10-11 
2012-10-20 - 2012-10-25 
2012-04-15 - 2012-04-16 
2012-05-20 - 2012-05-25 
2012-12-01 - 2012-12-10 
2012-10-23 - 2012-10-28 
2012-09-14 - 2012-10-28 
2012-11-13 - 2012-12-15 

这可能与SQL？

我使用SQL Server 2008

Answer 1

有了SQL Server它实际上是简单的：

SELECT startDate, endDate 
FROM YourTable 
WHERE '2012-10-25' between startDate and endDate 

Answer 2

检查BETWEEN关键字。

语法很简单：

SELECT col1, col2 
FROM table1 
WHERE date_col BETWEEN '2012-10-25' and 2012-10-28 

Answer 3

其他lappingcheck以下可能是有趣

Select * from sted where [dbo].[F_LappingDays](Startdate,EndDate,'20121025','20121025')=1 


CREATE Function [dbo].[F_LappingDays](@Von1 datetime,@bis1 Datetime,@von2 Datetime,@bis2 Datetime) Returns int as 
/* 
20110531 Thomas Wassermann 
Terminüberschneidungen finden 
*/ 
begin 
Declare @Result int 

Select @Result = 0 
if (@Von1>=@Von2) and (@bis1<=@Bis2) 
    begin 
     Select @Result=Cast(@Bis1 - @von1 + 1 as Int) 
    end 

else if (@Von1<=@Von2) and (@bis1 > @Von2) and (@bis1<=@Bis2) 
    begin 
     Select @Result=Cast(@Bis1 - @von2 + 1 as Int) 
    end 

else if (@Von1>=@Von2) and (@von1<=@bis2) and (@bis1>@Bis2) 
    begin 
     Select @Result=Cast(@Bis2 - @von1 + 1 as Int) 
    end 

else if (@Von1<@Von2) and (@bis1>@Bis2) 
    begin 
     Select @Result=Cast(@Bis2 - @von2 + 1 as Int) 
    end 



Return @Result 
end