2010-10-19 48 views
0

为什么这工作完美:MySQL的语法问题

SET @columnQuery = 'INSERT INTO ColumnNames SELECT ORDINAL_POSITION, COLUMN_NAME FROM information_schema.columns WHERE TABLE_NAME=''residents'' ORDER BY ORDINAL_POSITION;'; 

PREPARE STMT FROM @columnQuery; 
EXECUTE STMT; 

但这并不:

DECLARE TableName VARCHAR(50); 
SET @TableName = 'residents'; 

SET @columnQuery = 'INSERT INTO ColumnNames SELECT ORDINAL_POSITION, COLUMN_NAME FROM information_schema.columns WHERE TABLE_NAME=''' + @TableName + ''' ORDER BY ORDINAL_POSITION;'; 

PREPARE STMT FROM @columnQuery; 
EXECUTE STMT; 

,并没有做到这一点:

DECLARE TableName VARCHAR(50); 
SET @TableName = 'residents'; 

SET @columnQuery = CONCAT('INSERT INTO ColumnNames SELECT ORDINAL_POSITION, COLUMN_NAME FROM information_schema.columns WHERE TABLE_NAME=''', @TableName, ''' ORDER BY ORDINAL_POSITION;'); 

PREPARE STMT FROM @columnQuery; 
EXECUTE STMT; 

无论是做这个的:

SET @columnQuery = 'INSERT INTO ColumnNames SELECT ORDINAL_POSITION, COLUMN_NAME FROM information_schema.columns WHERE TABLE_NAME=? ORDER BY ORDINAL_POSITION;'; 

PREPARE STMT FROM @columnQuery; 
EXECUTE STMT USING @TableName; 

这是给我的问题存储过程的一部分:


CREATE PROCEDURE sp_ReturnSingleRowAsXml 
(
    IN TableName VARCHAR(50) 
) 
BEGIN 

DECLARE columnQuery VARCHAR(1000); 

DROP TABLE IF EXISTS ColumnNames; 

CREATE TEMPORARY TABLE ColumnNames (
    ID INT, ColumnName VARCHAR(50) 
); 

SET @columnQuery = 'INSERT INTO ColumnNames SELECT ORDINAL_POSITION, COLUMN_NAME FROM information_schema.columns WHERE TABLE_NAME=''' + @TableName + ''' ORDER BY ORDINAL_POSITION;'; 

PREPARE STMT FROM @columnQuery; 
EXECUTE STMT; 

select * from ColumnNames; 

END; 

CALL sp_ReturnSingleRowAsXml('residents'); 

的select返回没事的时候,它应该返回40行。但是,如果我在@columnQuery中硬编码“居民”这个词,我会得到结果!是的,肯定有一张名为“居民”的表。

有时候,我得到这个错误,有时我不知道,这取决于我是否使用CONCAT或只是手动连接字符串:

MySQL数据库错误:你在你的SQL语法错误;检查对应于你的MySQL服务器版本在1号线

回答

0

我能得到它具有以下工作:

CREATE PROCEDURE `sp_ReturnSingleRowAsXml`( 
    IN TableName VARCHAR(50) 
) 
BEGIN 

DROP TABLE IF EXISTS ColumnNames; 

CREATE TEMPORARY TABLE ColumnNames ( 
    ID INT, ColumnName VARCHAR(50) 
); 
SET @tblName = TableName; 
SET @columnQuery = 'INSERT INTO ColumnNames SELECT ORDINAL_POSITION, COLUMN_NAME FROM information_schema.columns WHERE TABLE_NAME=? ORDER BY ORDINAL_POSITION;'; 

PREPARE STMT FROM @columnQuery; 
EXECUTE STMT USING @tblName; 

select * from ColumnNames; 

END 
+0

太棒了!奇迹般有效。那么交易是什么?输入参数不能直接用于语句中?我必须先将它们放入局部变量中?奇怪的。 – Blackcoil 2010-10-19 18:00:42

0

使用近“NULL”正确的语法手册试试这个:

DECLARE TableName VARCHAR(50); 
SET @TableName = 'residents'; 

SET @columnQuery = 'INSERT INTO ColumnNames SELECT ORDINAL_POSITION, COLUMN_NAME FROM information_schema.columns WHERE TABLE_NAME=? ORDER BY ORDINAL_POSITION;'; 

PREPARE STMT FROM @columnQuery; 
EXECUTE STMT USING @TableName; 
+0

由于USING需要在EXECUTE之后才抛出错误。 – Blackcoil 2010-10-19 17:08:00

+0

我不好 - 我会更新。 – 2010-10-19 17:08:54

+0

它仍然无法正常工作。 :) – Blackcoil 2010-10-19 17:09:42