nativequery的替代namedquery

我需要在jpa中将我的查询从native-query更改为（named-query或create-query）。nativequery的替代namedquery

em = getEntityManager(); 

    String query = "SELECT kcu.table_Name FROM INFORMATION_SCHEMA.key_column_usage kcu,Information_schema.Tables kt " + 
      "WHERE kcu.REFERENCED_TABLE_NAME = 'sampleTable1' " + 
      "AND kcu.TABLE_SCHEMA='sampleDataBase' " + 
      "AND kcu.REFERENCED_COLUMN_NAME = 'sampleRollNoId' " + 
      "AND kt.table_name = kcu.table_name " + 
      "AND kt.table_rows > 0 " + 
      "AND kt.table_schema = kcu.table_schema"; 

    List tableNameList = (List) em.createNativeQuery(query).getResultList();

该查询返回所有表名（表名外键引用此表（sampleTable1））。

我有错误，当我改变的createQuery或namedQuery。

像

List tableNameList = (List) em.createQuery(query).getResultList(); 

or 

List tableNameList = (List) em.createNamedQuery(query).getResultList();

如何改变这种查询作为namedQuery或的createQuery。有可能吗？

以下错误，当我使用的createQuery

------------- Standard Error ----------------- 
log4j:WARN No appenders could be found for logger 
    (org.springframework.test.context.junit4.SpringJUnit4ClassRunner). 
log4j:WARN Please initialize the log4j system properly. 

Testcase: testEntryInUseNamedQuery(com.JPASampleDAOTest):  Caused an ERROR 
org.hibernate.hql.ast.QuerySyntaxException: INFORMATION_SCHEMA.key_column_usage is not mapped 

[SELECT kcu.table_Name FROM INFORMATION_SCHEMA.key_column_usage kcu,Information_schema.Tables kt WHERE kcu.REFERENCED_TABLE_NAME = 'sampleTable1' AND kcu.TABLE_SCHEMA='sampleDatabase' AND kcu.REFERENCED_COLUMN_NAME = 'sampleRollNoId' AND kt.table_name = kcu.table_name AND kt.table_rows > 0 AND kt.table_schema = kcu.table_schema] 

java.lang.IllegalArgumentException: org.hibernate.hql.ast.QuerySyntaxException: INFORMATION_SCHEMA.key_column_usage is not mapped [SELECT kcu.table_Name FROM INFORMATION_SCHEMA.key_column_usage kcu,Information_schema.Tables kt WHERE kcu.REFERENCED_TABLE_NAME = 'sampleTable1' AND kcu.TABLE_SCHEMA='sampleDatabase' AND kcu.REFERENCED_COLUMN_NAME = 'sampleRollNoId' AND kt.table_name = kcu.table_name AND kt.table_rows > 0 AND kt.table_schema = kcu.table_schema] 
    at org.hibernate.ejb.AbstractEntityManagerImpl.throwPersistenceException(AbstractEntityManagerImpl.java:624) 
    at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:96) 
    at org.springframework.orm.jpa.SharedEntityManagerCreator$SharedEntityManagerInvocationHandler.invoke(SharedEntityManagerCreator.java:193) 
    at $Proxy27.createQuery(Unknown Source) 
at org.springframework.test.context.junit4.SpringTestMethod.invoke(SpringTestMethod.java:198) 
    at org.springframework.test.context.junit4.SpringMethodRoadie.runTestMethod(SpringMethodRoadie.java:274) 
    at org.springframework.test.context.junit4.SpringMethodRoadie$2.run(SpringMethodRoadie.java:207) 
    at org.springframework.test.context.junit4.SpringMethodRoadie.runBeforesThenTestThenAfters(SpringMethodRoadie.java:254) 
    at org.springframework.test.context.junit4.SpringMethodRoadie.runWithRepetitions(SpringMethodRoadie.java:234) 
    at org.springframework.test.context.junit4.SpringMethodRoadie.runTest(SpringMethodRoadie.java:204) 
    at org.springframework.test.context.junit4.SpringMethodRoadie.run(SpringMethodRoadie.java:146) 
    at org.springframework.test.context.junit4.SpringJUnit4ClassRunner.invokeTestMethod(SpringJUnit4ClassRunner.java:151) 

Caused by: org.hibernate.hql.ast.QuerySyntaxException: INFORMATION_SCHEMA.key_column_usage is not mapped [SELECT kcu.table_Name FROM INFORMATION_SCHEMA.key_column_usage kcu,Information_schema.Tables kt WHERE kcu.REFERENCED_TABLE_NAME = 'sampleTable1' AND kcu.TABLE_SCHEMA='sampleDatabase' AND kcu.REFERENCED_COLUMN_NAME = 'sampleRollNoId' AND kt.table_name = kcu.table_name AND kt.table_rows > 0 AND kt.table_schema = kcu.table_schema] 
    at org.hibernate.hql.ast.util.SessionFactoryHelper.requireClassPersister(SessionFactoryHelper.java:158) 
    at org.hibernate.hql.ast.tree.FromElementFactory.addFromElement(FromElementFactory.java:87) 
    at org.hibernate.hql.ast.tree.FromClause.addFromElement(FromClause.java:70) 
    at org.hibernate.hql.ast.HqlSqlWalker.createFromElement(HqlSqlWalker.java:255) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElement(HqlSqlBaseWalker.java:3056) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromElementList(HqlSqlBaseWalker.java:2945) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.fromClause(HqlSqlBaseWalker.java:688) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:544) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:281) 
    at org.hibernate.hql.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:229) 
    at org.hibernate.hql.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:228) 
    at org.hibernate.hql.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:160) 
    at org.hibernate.hql.ast.QueryTranslatorImpl.compile(QueryTranslatorImpl.java:111) 
    at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:77) 
    at org.hibernate.engine.query.HQLQueryPlan.<init>(HQLQueryPlan.java:56) 
    at org.hibernate.engine.query.QueryPlanCache.getHQLQueryPlan(QueryPlanCache.java:72) 
    at org.hibernate.impl.AbstractSessionImpl.getHQLQueryPlan(AbstractSessionImpl.java:133) 
    at org.hibernate.impl.AbstractSessionImpl.createQuery(AbstractSessionImpl.java:112) 
    at org.hibernate.impl.SessionImpl.createQuery(SessionImpl.java:1623) 
    at org.hibernate.ejb.AbstractEntityManagerImpl.createQuery(AbstractEntityManagerImpl.java:93)

帮帮我，在此先感谢。

来源

2012-06-29 jackrobert

您遇到过什么错误？ –

感谢JR Galia的回应。现在我在我的问题中添加了错误 – jackrobert

使用JPQL了SQL。在JPQL中，您指的是实体而不是表格和属性而不是列。

使用em.createQuery()执行JPQL查询。 em.createNamedQuery(）是为了不同的目的。

来源

2012-06-29 08:55:47 JMelnik

nativequery的替代namedquery

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