在数组中搜索字符串

Question

我试图更改包含数组（城市名称）值的字符串（城市）。

代码：

for ($i=0; $i<$1000; $i++) { 

$cities = "I live in Prag"; 
$array = array("Wien","Prag","Berlin"); 
foreach ($array AS $val) { 

     if (preg_match("/".$val."/", $cities)) { 
     $cities = str_replace($val, ", " . $val. ", ", $cities);  
     } 
    } 
} 

有另一种解决方案？

感谢

Answer 1

下面是使用preg_replace和implode功能的简单的解决方案：

$cities = "I live in Prag but love Wien"; 
$array = array("Wien","Prag","Berlin"); 
$cities = preg_replace("/\b". implode("|", $array) ."\b/", ',$0,', $cities); 

print_r($cities); // "I live in ,Prag, but love ,Wien," 

Answer 2

如果你需要找到符合条件的值的键，那么你需要循环数组过来，让这样使用。

$example = array('An example','Another example','One Example','Last example'); 
$searchword = 'last'; 
$matches = array(); 
foreach($example as $k=>$v) { 
    if(preg_match("/\b$searchword\b/i", $v)) { 
     $matches[$k] = $v; 
    } 
} 

Answer 3

我想......

$cities = "I live in Prag"; 
$array = array("Wien","Prag","Berlin"); 
foreach ($array AS $val) { 

    $cities = preg_replace("/(.*)(" . $val . ")(.*)/", "$1, $2, $3", $cities); 
} 

Echo $cities; 

可以做到这一点。

编辑工作示例：https://3v4l.org/0eDDW