2013-07-09 41 views
0

我们有两个MySQL表来跟踪我们每天的横幅统计数据。一张表格用于观看,另一张用于点击。这两个表设置这样的:将两个表合并为一个

次数:

banner_id (int 11) 
click_date (date) 
click_total (int 11) 

浏览:

banner_id (int 11) 
view_date (date) 
view_total (int 11) 

我需要每个月获得的统计信息;为此我得到了这个查询(对于视图):

SELECT 
    bv.`view_date`, 
    SUM(bv.`view_total`) AS view_total 
FROM 
    tarlo.`tarlo_banners_views` bv 
WHERE bv.`banner_id` = 469 
GROUP BY bv.`banner_id` 
ORDER BY bv.`view_date` ASC ; 

而对于点击我有一个查询看起来几乎相同。在PHP中,我们将日期的结果合并到一个数组中。现在我们想知道是否可以通过一个MySQL查询(而不是2)来结合结果。

因此,我们需要的结果是这样的:

Date:  Clicks: Views: 
2013-07-07 556  156833 
2013-07-08 726  175683 
2013-07-09 356  130588 

,而不是2分的结果集这样的:

Date:  Clicks: 
2013-07-07 556 
2013-07-08 726 
2013-07-09 356 

Date:  Views: 
2013-07-07 156833 
2013-07-08 175683 
2013-07-09 130588 

我们怎样才能做到这一点?

回答

1

喜欢的东西:

SELECT 
    bv.`view_date`, 
    SUM(bv.`view_total`) AS view_total, 
    SUM(bc.`click_total`) AS click_total, 
FROM 
    tarlo.`tarlo_banners_views` bv, tarlo.`tarlo_banners_clicks` bc 
WHERE bv.`banner_id` = 469 
AND bc.`banner_id` = bv.`banner_id` 
AND bc.`click_date` = bv.`view_date` 
GROUP BY bv.`banner_id` 
ORDER BY bv.`view_date` ASC ; 
+0

优秀,可以完美运行! –

0

您需要JOIN两个表所示:

SELECT 
    bv.`view_date`, 
    SUM(bv.`view_total_views`) AS view_total_views, 
    SUM(bc.`view_total_clicks`) AS view_total_click 
FROM 
    tarlo.`tarlo_banners_views` bv 
JOIN 
    tarlo.`tarlo_banners_clicks` bc 
WHERE bv.`banner_id` = 469 
GROUP BY bv.`banner_id` 
ORDER BY bv.`view_date` ASC ;