NoSuchBeanDefinitionException同时建立一个简单的Spring JPA项目

我沿着下面的教程如下： https://spring.io/guides/gs/accessing-data-jpa/NoSuchBeanDefinitionException同时建立一个简单的Spring JPA项目

我使用Maven，Spring和JPA创建基于样本内存数据库。我有以下课程;

模型类：

import javax.persistence.Entity; 
import javax.persistence.GeneratedValue; 
import javax.persistence.GenerationType; 
import javax.persistence.Id; 

@Entity 
public class Customer { 
    @Id 
    @GeneratedValue(strategy=GenerationType.AUTO) 
    private long id; 
    public long getId() { return this.id; } 
    public void setId(long Id) { this.id = Id; } 

    private String firstName; 
    public String getFirstName() { return this.firstName; } 
    public void setFirstName(String FirstName) { this.firstName = FirstName; } 

    private String lastName; 
    public String getLastName() { return this.lastName; } 
    public void setLastName(String LastName) { this.lastName = LastName; } 

    public Customer(String firstname, String lastname) { 
     super(); 
     this.firstName = firstname; 
     this.lastName = lastname; 
    } 

    public Customer() { 
     super(); 
    } 

    @Override 
    public String toString() { 
     return String.format(
       "Customer[id=%d, firstName='%s', lastName='%s']", 
       id, firstName, lastName); 
    } 
}

CustomerRepository类

import java.util.List; 

import org.springframework.data.repository.CrudRepository; 

import com.accenture.cursojava.modelos.Customer; 

public interface CustomerRepository extends CrudRepository<Customer, Long>{ 
    List<Customer> findByLastName(String lastName); 
}

应用类别：

import org.springframework.boot.SpringApplication; 
import org.springframework.boot.autoconfigure.EnableAutoConfiguration; 
import org.springframework.context.ConfigurableApplicationContext; 
import org.springframework.context.annotation.Configuration; 

import com.accenture.cursojava.dataaccess.CustomerRepository; 
import com.accenture.cursojava.modelos.Customer; 

@Configuration 
@EnableAutoConfiguration 
public class Application { 
    public static void main(String[] args) { 
     ConfigurableApplicationContext context = SpringApplication.run(Application.class, args); 
     CustomerRepository repository = context.getBean(CustomerRepository.class); 
     repository.save(new Customer("Cliente", "de Prueba 1")); 
     repository.save(new Customer("Cliente", "de Prueba 2")); 
     repository.save(new Customer("Cliente", "de Prueba 3")); 
     repository.save(new Customer("Cliente", "de Prueba 4")); 
     repository.save(new Customer("Cliente", "de Prueba 1")); 
     repository.save(new Customer("Cliente", "de Prueba 2")); 
     repository.save(new Customer("Cliente", "de Prueba 3")); 
     repository.save(new Customer("Cliente", "de Prueba 4")); 

     Iterable<Customer> clientes = repository.findAll(); 
     for (Customer customer : clientes) { 
      System.out.println(customer.getFirstName()); 
      System.out.println(customer.getLastName()); 
     } 
     Iterable<Customer> clientes1 = repository.findByLastName("de Prueba 1"); 
     for (Customer customer : clientes1) { 
      System.out.println(customer.getFirstName()); 
      System.out.println(customer.getLastName()); 
     } 
     context.close(); 
    } 
}

执行代码，并沿酷似教程指出以下后，我得到的以下输出：

Exception in thread "main" org.springframework.beans.factory.NoSuchBeanDefinitionException: No qualifying bean of type [com.myapplication.CustomerRepository] is defined 
    at org.springframework.beans.factory.support.DefaultListableBeanFactory.getBean(DefaultListableBeanFactory.java:319) 
    at org.springframework.context.support.AbstractApplicationContext.getBean(AbstractApplicationContext.java:987) 
    at com.myapplication.Application.main(Application.java:18)

任何想法可能是罪魁祸首？

来源

2014-09-26 sgarcia.dev

你不应该注释你的代码['@ EnableJpaRepositories']（http://docs.spring.io/spring-data/jpa/docs/current/api/org/springframework/data/jpa/repository/config/EnableJpaRepositories.html）？ – 2014-09-26 22:36:28

您是否实现了界面？我不相信你可以创建接口的实例... – 2014-09-26 22:36:31

@CharlesSmartt这是一个[弹簧数据]（http://projects.spring.io/spring-data-jpa/）功能。它实现了引擎盖下的界面，当你要求它时，它会给你一个代理。这是一个美丽的:-) – 2014-09-26 22:37:56

Spring对这个bean CustomerRepository没有任何了解。你需要告诉Spring它是一个托管bean。您可以通过添加@Repository注释来完成此操作。

@Repository 
public interface CustomerRepository extends CrudRepository<Customer, Long>{ 
    List<Customer> findByLastName(String lastName); 
}

您可能还需要告诉Spring到哪里寻找注释类（虽然也许@EnableAutoConfiguiration使不必要的 - 我不熟悉）

@Configuration 
@EnableAutoConfiguration 
@EnableJpaRepositories()//specify the base package containing your repository interfaces. 
public class Application { 

}

来源

2014-09-27 08:57:34

NoSuchBeanDefinitionException同时建立一个简单的Spring JPA项目

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