获得最高值 - MySQL的

Question

我有这个疑问：

SELECT tag, filename, timecode, COUNT(tag) AS total 
FROM dados 
WHERE dados.tag = 'movie' 
AND dados.filename = 'movie2.mp4' 
GROUP BY timecode 

这是结果：

但我只想在第三排，更精确的时间码= 2，因为它是具有较高值的​​组合最多的标签。 如何从这些行中获取时间码的最高值？

Answer 1

使用ORDER BY与LIMIT

SELECT tag, filename, timecode, COUNT(tag) AS total 
FROM dados 
WHERE dados.tag = 'movie' 
AND dados.filename = 'movie2.mp4' 
GROUP BY timecode 
ORDER BY COUNT(tag) DESC 
LIMIT 1