在GAS中合并2个JSON对象（无jquery）

Question

如何合并2个（结构相同）的JSON对象（在Google Spreadsheet脚本中）？

{"records":[{"id":28100988,"work_text_reviews_count":13,"average_rating":"3.10"},{"id":10280687,"work_text_reviews_count":80,"average_rating":"3.87"}]} 

{"records":[{"id":16135639,"work_text_reviews_count":0,"average_rating":"0.00"},{"id":17978337,"work_text_reviews_count":2414,"average_rating":"3.76"{"id":360721218,"work_text_reviews_count":4924,"average_rating":"3.98"}]} 

合并后的结果应该是：

{"records":[{"id":28100988,"work_text_reviews_count":13,"average_rating":"3.10"},{"id":10280687,"work_text_reviews_count":80,"average_rating":"3.87"},{"id":16135639,"work_text_reviews_count":0,"average_rating":"0.00"},{"id":360721218,"work_text_reviews_count":4924,"average_rating":"3.98"}]} 

由于这在谷歌电子表格，我不能使用JQuery，我已经用了一整天的JavaScript的解决方案，我不能让工作没有错误。

Answer 1

你可以使用concat：

var json1 = { 
    "records": [{ 
    "id": 28100988, 
    "work_text_reviews_count": 13, 
    "average_rating": "3.10" 
    }, { 
    "id": 10280687, 
    "work_text_reviews_count": 80, 
    "average_rating": "3.87" 
    }] 
} 

var json2 = { 
    "records": [{ 
    "id": 16135639, 
    "work_text_reviews_count": 0, 
    "average_rating": "0.00" 
    }, { 
    "id": 17978337, 
    "work_text_reviews_count": 2414, 
    "average_rating": "3.76" 
    }, { 
    "id": 360721218, 
    "work_text_reviews_count": 4924, 
    "average_rating": "3.98" 
    }] 
} 


var json3 = json1.records.concat(json2.records);