2
我在表“OG”中有一列“名称”和“ids”,并且希望找到最后一个字母不同且总编辑距离为两个的那些名称。到目前为止,我有:设置一个字符串的最后一个字母等于PostgreSQL
SELECT
z1.names as names1, z2.names as names2, z1.ids, z2.ids
FROM (SELECT t.names, SUBSTRING(t.names for Length(t.names-1) AS newnames
from "OG" t) z1, (SELECT r.names, SUBSTRING(r.names for Length(r.names-1) AS
newnames1 FROM "OG" r) z2
WHERE levenshtein(z1.newnames, z2.newnames1) = 2 AND z1.id != z2.id
不幸的是,这并不能确保最后的字母是不同的。任何想法修复?
超爽!谢谢! – 2011-04-03 21:55:41