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我想根据前2个选择框选择(动态值)获取第3个选择框值;如何通过ajax发送2个选择框动态生成的值以获得第3个选择框值
jQuery的Ajax代码是(这仅与机场选择框作品)
$("#airport").change(function() {
var aid=$(this).val();
var dataString = 'aid='+ aid;
$.ajax
({
type: "POST",
url: "booking/findcompany.php",
data: dataString,
cache: false,
success: function(data) {
$("#company").html(data);
}
});
});
<select name="site" id="site" class="site">
<option value="" selected="selected">Select</option>
<option value="1">Site One</option>
<option value="2">Site Two</option>
<option value="3">Site Three</option>
</select>
<select name="airport" id="airport" class="airport">
<option value="1">Airport One</option>
<option value="2">Airport Two</option>
<option value="3">Airport Three</option>
</select>
<select name="company" id="company" class="company">
//Options here based on above 2 selected values
</select>
PHP代码findcompany.php
<?php
if($_POST['aid']) {
$aid=$_POST['aid'];
$site=$_POST['sid']; <<<<<< How Can I pass This ID
$compsql=mysql_query("select * from tbl_company Where air_id='$aid' and site_id='$sid'");
while($rows=mysql_fetch_array($compsql)){
$cid=$rows['comp_id'];
$cdata=$rows['comp_title'];
?>
<option value="<?php echo $cid; ?>"><?php echo $cdata; ?></option>
<?php } } ?>
非常感谢解决方案。 – Shehary 2015-09-01 20:27:13