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我有这样的代码在本地做出反应React Native如何将状态恢复为默认状态?
class Home extends Component {
constructor(props) {
super(props);
this.initialState={
backGroundColor: '#ffffff',
visible:[true,true,true,true,true,true],
progress:0,
numbers: shuffle([1,2,3,4,5,6])
}
this.state = this.initialState;
}
_resetState(){
this.setState(this.initialState);
}
_change(teste,op){
if(op==this.state.numbers[0]){
let array = this.state.visible;
switch(op){
case 1:
array[op-1] = false;
break;
case 2:
array[op-1] = false;
break;
case 3:
array[op-1] = false;
break;
case 4:
array[op-1] = false;
break;
case 5:
array[op-1] = false;
break;
case 6:
array[op-1] = false;
break;
}
this.setState({backGroundColor: teste,visible:array,progress: this.state.progress+0.16666666666666});
this.state.numbers.splice(0,1);
}else{
console.log(this.initialState);
}
}
当我做的console.log(this.initialState)的阵列数量和可见里面的状态不是初始但BACKGROUNDCOLOR和进步是初始值。为什么会发生?我怎样才能保持他们的初始值?我需要回到初始状态的所有元素(包括两个数组)。