我想添加一个非常简单的文件输入到我的webapp，我正在使用JSF2.0和RichFaces 3.3.3，事情是我真的不喜欢richfaces fileInput组件和我在找更简单的东西（在使用方面，看起来），到目前为止，我发现：JSF2.0简单文件输入
还有其他的选择吗？我需要一些非常简单的东西，比如普通的html文件输入组件。
使自定义组件在JSF基本上，您需要做两件事情：
创建这使在multipart/form-data项的过滤器自定义映射并用它替换原始请求参数映射，以便正常request.getParameter()进程继续工作。
创建一个JSF 2.0自定义组件，它呈现input type="file"并知道此自定义映射并可以从其获取上传的文件。
@taher已经给出了一个链接，您可以在其中找到洞察和代码片段。 JSF 2.0片段应该是可重用的。您还必须修改MultipartMap才能使用良好的ol Apache Commons FileUpload API而不是Servlet 3.0 API。
如果我有时间，我会在一天结束时重写它并将其发布到此处。
更新：我几乎忘了你，我做了一个快速更新以取代通用FileUpload API的Servlet 3.0 API，它应该工作：
package net.balusc.http.multipart;
import java.io.BufferedInputStream;
import java.io.BufferedOutputStream;
import java.io.File;
import java.io.FileOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.util.Arrays;
import java.util.Collections;
import java.util.Enumeration;
import java.util.HashMap;
import java.util.List;
import java.util.Map;
import java.util.Map.Entry;
import javax.servlet.ServletException;
import javax.servlet.ServletRequest;
import javax.servlet.http.HttpServletRequest;
import org.apache.commons.fileupload.FileItem;
import org.apache.commons.fileupload.FileUploadException;
import org.apache.commons.fileupload.disk.DiskFileItemFactory;
import org.apache.commons.fileupload.servlet.ServletFileUpload;
import org.apache.commons.io.FilenameUtils;
import org.apache.commons.io.IOUtils;
public class MultipartMap extends HashMap<String, Object> {
// Constants ----------------------------------------------------------------------------------
private static final String ATTRIBUTE_NAME = "parts";
private static final String DEFAULT_ENCODING = "UTF-8";
private static final int DEFAULT_BUFFER_SIZE = 10240; // 10KB.
// Vars ---------------------------------------------------------------------------------------
private String encoding;
private String location;
// Constructors -------------------------------------------------------------------------------
/**
* Construct multipart map based on the given multipart request and file upload location. When
* the encoding is not specified in the given request, then it will default to <tt>UTF-8</tt>.
* @param multipartRequest The multipart request to construct the multipart map for.
* @param location The location to save uploaded files in.
* @throws ServletException If something fails at Servlet level.
* @throws IOException If something fails at I/O level.
*/
@SuppressWarnings("unchecked") // ServletFileUpload#parseRequest() isn't parameterized.
public MultipartMap(HttpServletRequest multipartRequest, String location)
throws ServletException, IOException
{
multipartRequest.setAttribute(ATTRIBUTE_NAME, this);
this.encoding = multipartRequest.getCharacterEncoding();
if (this.encoding == null) {
multipartRequest.setCharacterEncoding(this.encoding = DEFAULT_ENCODING);
}
this.location = location;
try {
List<FileItem> parts = new ServletFileUpload(new DiskFileItemFactory()).parseRequest(multipartRequest);
for (FileItem part : parts) {
if (part.isFormField()) {
processFormField(part);
} else if (!part.getName().isEmpty()) {
processFileField(part);
}
}
} catch (FileUploadException e) {
throw new ServletException("Parsing multipart/form-data request failed.", e);
}
}
// Actions ------------------------------------------------------------------------------------
@Override
public Object get(Object key) {
Object value = super.get(key);
if (value instanceof String[]) {
String[] values = (String[]) value;
return values.length == 1 ? values[0] : Arrays.asList(values);
} else {
return value; // Can be File or null.
}
}
/**
* @see ServletRequest#getParameter(String)
* @throws IllegalArgumentException If this field is actually a File field.
*/
public String getParameter(String name) {
Object value = super.get(name);
if (value instanceof File) {
throw new IllegalArgumentException("This is a File field. Use #getFile() instead.");
}
String[] values = (String[]) value;
return values != null ? values[0] : null;
}
/**
* @see ServletRequest#getParameterValues(String)
* @throws IllegalArgumentException If this field is actually a File field.
*/
public String[] getParameterValues(String name) {
Object value = super.get(name);
if (value instanceof File) {
throw new IllegalArgumentException("This is a File field. Use #getFile() instead.");
}
return (String[]) value;
}
/**
* @see ServletRequest#getParameterNames()
*/
public Enumeration<String> getParameterNames() {
return Collections.enumeration(keySet());
}
/**
* @see ServletRequest#getParameterMap()
*/
public Map<String, String[]> getParameterMap() {
Map<String, String[]> map = new HashMap<String, String[]>();
for (Entry<String, Object> entry : entrySet()) {
Object value = entry.getValue();
if (value instanceof String[]) {
map.put(entry.getKey(), (String[]) value);
} else {
map.put(entry.getKey(), new String[] { ((File) value).getName() });
}
}
return map;
}
/**
* Returns uploaded file associated with given request parameter name.
* @param name Request parameter name to return the associated uploaded file for.
* @return Uploaded file associated with given request parameter name.
* @throws IllegalArgumentException If this field is actually a Text field.
*/
public File getFile(String name) {
Object value = super.get(name);
if (value instanceof String[]) {
throw new IllegalArgumentException("This is a Text field. Use #getParameter() instead.");
}
return (File) value;
}
// Helpers ------------------------------------------------------------------------------------
/**
* Process given part as Text part.
*/
private void processFormField(FileItem part) {
String name = part.getFieldName();
String[] values = (String[]) super.get(name);
if (values == null) {
// Not in parameter map yet, so add as new value.
put(name, new String[] { part.getString() });
} else {
// Multiple field values, so add new value to existing array.
int length = values.length;
String[] newValues = new String[length + 1];
System.arraycopy(values, 0, newValues, 0, length);
newValues[length] = part.getString();
put(name, newValues);
}
}
/**
* Process given part as File part which is to be saved in temp dir with the given filename.
*/
private void processFileField(FileItem part) throws IOException {
// Get filename prefix (actual name) and suffix (extension).
String filename = FilenameUtils.getName(part.getName());
String prefix = filename;
String suffix = "";
if (filename.contains(".")) {
prefix = filename.substring(0, filename.lastIndexOf('.'));
suffix = filename.substring(filename.lastIndexOf('.'));
}
// Write uploaded file.
File file = File.createTempFile(prefix + "_", suffix, new File(location));
InputStream input = null;
OutputStream output = null;
try {
input = new BufferedInputStream(part.getInputStream(), DEFAULT_BUFFER_SIZE);
output = new BufferedOutputStream(new FileOutputStream(file), DEFAULT_BUFFER_SIZE);
IOUtils.copy(input, output);
} finally {
IOUtils.closeQuietly(output);
IOUtils.closeQuietly(input);
}
put(part.getFieldName(), file);
part.delete(); // Cleanup temporary storage.
}
}
你仍然需要两个MultipartFilter和MultipartRequest如this article中所述。您只需要删除@WebFilter注释，并将url-pattern的url-pattern和<init-param>的<init-param>映射到，其中您指定要存储上载文件的绝对路径。您可以使用未更改的this article中描述的JSF 2.0定制文件上载组件。
亲爱要么你必须使用丰富：uploadFile或以下http://balusc.blogspot.com/2009/12/uploading-files-with-jsf-20-and-servlet.html
这里的问题是我使用Tomcat 6，它不支持Servlet 3.0（和这不是我的电话转换到tomcat 7）。 – 2010-08-12 08:54:26
我也试过tomahawk后，我提到它不适用于AJAX。所以我决定破解rich：fileUpload并在a4j：commandButton上执行点击添加按钮。下面的代码：
<a4j:form id="myForm">
<a4j:commandButton id="myButton" value="Upload" title="Upload" styleClass="myButtonClass"
onclick="document.getElementById('myForm:myFileUpload:file').click()/>
<rich:fileUpload id="myFileUpload" maxFilesQuantity="1" autoclear="true"
immediateUpload="true" styleClass="invisibleClass"
fileUploadListener="#{uploadBean.uploadListener}"/>
</a4j:form>
myForm:myFileUpload:file是输入元素（type="file"）的附加按钮。 invisibleClass应该只包含display:none;。随着style="display:none;"它不会工作。
You can used rich faces 3.3.3 file upload.
步骤1：fileUpload.xhtml
<rich:fileUpload id="fileupload" addControlLabel="Browse"
required="true"
fileUploadListener="#{testForm.listener}"
acceptedTypes="xml"
ontyperejected="alert('Only xml files are accepted');"
maxFilesQuantity="1" listHeight="57px" listWidth="100%"
disabled="#{testForm..disabled}" >
<a4j:support event="onclear"
action="#{testForm..clearUploadData}"
reRender="fileupload" />
</rich:fileUpload>
步骤2：FileUpload.java
public class FileUpload implements Serializable{
/**
*
*/
private static final long serialVersionUID = 1L;
private String Name;
private String mime;
private long length;
private byte [] file;
private String absolutePath;
public String getName() {
return Name;
}
/**
* @return the file
*/
public byte[] getFile() {
return file;
}
/**
* @param file the file to set
*/
public void setFile(byte[] file) {
this.file = file;
}
/**
* @param mime the mime to set
*/
public void setMime(String mime) {
this.mime = mime;
}
public void setName(String name) {
Name = name;
int extDot = name.lastIndexOf('.');
if(extDot > 0){
String extension = name.substring(extDot +1);
if("txt".equals(extension)){
mime="txt";
} else if("xml".equals(extension)){
mime="xml";
} else {
mime = "unknown file";
}
}
}
public long getLength() {
return length;
}
public void setLength(long length) {
this.length = length;
}
public String getMime(){
return mime;
}
/**
* @return the absolutePath
*/
public String getAbsolutePath() {
return absolutePath;
}
/**
* @param absolutePath the absolutePath to set
*/
public void setAbsolutePath(String absolutePath) {
this.absolutePath = absolutePath;
}
}
步骤3：TESTFORM //调用听者
/**
*
* @param event
* @throws Exception
*/
public void listener(UploadEvent event) throws Exception{
UploadItem item = event.getUploadItem();
FileUpload file = new FileUpload();
file.setLength(item.getData().length);
file.setFile(item.getData());
file.setName(item.getFileName());
files.add(file);
}
你读过这个问题了吗？ OP明确表示他不想使用它。 – BalusC 2014-02-05 09:16:44
感谢BalusC，如果你说用Apache Commons FileUpload替换MultipartMap，那么我想我会尝试一下！ – 2010-08-12 22:17:03
如果没有创建自定义组件，这可以做到吗？我更愿意使用jsf-2 api而不指定供应商，这似乎需要构建自定义组件，如[link]（http://balusc.blogspot.com/2009/12/uploading- files-with-jsf-20-and-servlet.html） – 2011-05-03 09:18:48
@Rasmus：是的，但你至少需要一个过滤器，将多部分部分作为请求参数。在不创建自定义组件的情况下，您自己负责收集并验证提交的值并更新模型值并调用任何侦听器。 – BalusC 2011-05-03 10:31:41