我正在编写一个僵尸程序,它将遵循www.quora.com上的用户。以下是我使用的代码部分在那里我得到超时异常:如何处理python中的超时异常
from selenium import webdriver
from selenium.webdriver.common.keys import Keys
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
import time
import urllib
driver = webdriver.Firefox()
driver.get('http://www.quora.com/')
time.sleep(10)
wait = WebDriverWait(driver, 10)
form = driver.find_element_by_class_name('regular_login')
time.sleep(10)
#add explicit wait
username = form.find_element_by_name('email')
time.sleep(10)
#add explicit wait
username.send_keys('[email protected]')
time.sleep(30)
#add explicit wait
password = form.find_element_by_name('password')
time.sleep(30)
#add explicit wait
password.send_keys('def')
time.sleep(30)
#add explicit wait
password.send_keys(Keys.RETURN)
time.sleep(30)
#search = driver.find_element_by_name('search_input')
search = wait.until(EC.presence_of_element_located((By.XPATH, "//form[@name='search_form']//input[@name='search_input']")))
search.clear()
search.send_keys('Kevin Rose')
search.send_keys(Keys.RETURN)
link = wait.until(EC.presence_of_element_located((By.LINK_TEXT, "Kevin Rose")))
link.click()
#Wait till the element is loaded (Asynchronusly loaded webpage)
handle = driver.window_handles
driver.switch_to.window(handle[1])
#switch to new window
element = WebDriverWait(driver, 2).until(EC.presence_of_element_located((By.PARTIAL_LINK_TEXT, "Followers")))
time.sleep(30)
element.click()
#goes to Kevin Rose followers page
time.sleep(30)
button = driver.find_elements_by_xpath("//a[contains(text(), 'Follow')]")
#Locate follow button on the page
no_of_followers = len(button)
#total number of unfollowed users
print no_of_followers
while(no_of_followers > 0):
# execute only if there are unfollowed users on page
count = 1
while(count < no_of_followers):
time.sleep(30)
link = wait.until(EC.presence_of_element_located((By.LINK_TEXT, "Follow")))
time.sleep(30)
link.click()
time.sleep(30)
print count
count = count + 1
time.sleep(30)
driver.execute_script("window.scrollTo(0, document.body.scrollHeight);")
time.sleep(30)
button = driver.find_elements_by_xpath("//a[contains(text(), 'Follow')]")
time.sleep(30)
no_of_followers = len(button)
执行的代码后,我得到在成功执行一次之后内环“TimeoutException异常”的错误。
我该如何解决这个问题?
回溯:
回溯(最近最后调用):文件 “C:\ Python27 \ quorabot7”, 线72,在 链路= wait.until(EC.presence_of_element_located((By.LINK_TEXT ,“Follow”))) “C:\ Python27 \ lib \ site-packages \ selenium \ webdriver \ support \ wait.py”
请包含完整的Traceback。 – dano 2014-09-19 17:24:09
另外,请发布完整的代码,以便我们可以复制它并逐步进行调试。谢谢。 – alecxe 2014-09-19 17:26:08
发布完整的代码和追溯。 – Siddhesh 2014-09-19 17:29:10