1
我有这个工作查询:SQL查询连接用笨的活动记录
$q = $this->db->query('SELECT u.name FROM users u
JOIN user_group ug ON u.id = ug.user_id
JOIN groups g ON g.id = ug.group_id WHERE ug.group_id = "4" ');
而且我想aactive记录来取代它。我想出了这样的事情,但显然它不工作:
$this->db->select('name');
$this->db->from('users');
$this->db->join('user_group', 'user_group.user_id = users.id);
$this->db->join('groups', 'groups.id = user_group.group_id');
$q = $this->db->get();
感谢 Leron
呀,这工作得很好。谢谢! – Leron 2012-03-29 20:50:05