您好我对C++来说比较陌生,在学习一些Java基础知识之后我才开始学习它。 我有预先存在的代码,它已经超载了>>
运营商,但是在看了很多教程并试图理解这个问题后,我想我会在这里问。新的C++和重载操作符,不确定如何使用函数
理性CPP文件:
#include "Rational.h"
#include <iostream>
Rational::Rational(){
}
Rational::Rational (int n, int d) {
n_ = n;
d_ = d;
}
/**
* Creates a rational number equivalent to other
*/
Rational::Rational (const Rational& other) {
n_ = other.n_;
d_ = other.d_;
}
/**
* Makes this equivalent to other
*/
Rational& Rational::operator= (const Rational& other) {
n_ = other.n_;
d_ = other.d_;
return *this;
}
/**
* Insert r into or extract r from stream
*/
std::ostream& operator<< (std::ostream& out, const Rational& r) {
return out << r.n_ << '/' << r.d_;
}
std::istream& operator>> (std::istream& in, Rational& r) {
int n, d;
if (in >> n && in.peek() == '/' && in.ignore() && in >> d) {
r = Rational(n, d);
}
return in;
}}
Rational.h文件:
#ifndef RATIONAL_H_
#define RATIONAL_H_
#include <iostream>
class Rational {
public:
Rational();
/**
* Creates a rational number with the given numerator and denominator
*/
Rational (int n = 0, int d = 1);
/**
* Creates a rational number equivalent to other
*/
Rational (const Rational& other);
/**
* Makes this equivalent to other
*/
Rational& operator= (const Rational& other);
/**
* Insert r into or extract r from stream
*/
friend std::ostream& operator<< (std::ostream &out, const Rational& r);
friend std::istream& operator>> (std::istream &in, Rational& r);
private:
int n_, d_;};
#endif
的功能是从一个称为理性预先存在的类,它需要两个int
S作为参数。下面是函数重载>>
:
std::istream& operator>> (std::istream& in, Rational& r) {
int n, d;
if (in >> n && in.peek() == '/' && in.ignore() && in >> d) {
r = Rational(n, d);
}
return in;
}
而且我尝试使用它这个样子,看到了一些教程后。 (我得到的错误是在"Ambiguous overload for operator>>
std::cin>>n1
:
int main() {
// create a Rational Object.
Rational n1();
cin >> n1;
}
就像我说我是新来的这整个重载运营商的事情上,拿捏有人在这里将能够指出我在正确的方向上如何使用此功能。
哇!如果它出现在我的代码中,我绝不会追踪它。 – 2013-04-29 19:46:38
@Jesse:很好! – 2013-04-29 19:47:10
@NemanjaBoric,当然可以。这通常与打开编译器警告一样简单。 – chris 2013-04-29 19:47:15