与曲线旋转matplotlib pyplot 90度

Question

我有情节与一个行这样的：

import numpy as np 
import matplotlib.pyplot as pl 

a = np.array([4, 4, 4, 4, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 8, 8, 8, 9]) 
b = np.array([i/len(a) for i in range(1, len(a)+1)]) 
aa = np.array([i/10 for i in range(40, 91)]) 
ss = np.array([ 0.06200455, 0.07389492, 0.08721351, 0.10198928, 0.11823225, 
       0.13593267, 0.15506088, 0.1755675 , 0.19738431, 0.22042543, 
       0.244589 , 0.26975916, 0.29580827, 0.32259936, 0.34998862, 
       0.377828 , 0.40596767, 0.43425846, 0.46255411, 0.49071331, 
       0.51860153, 0.54609255, 0.57306977, 0.5994272 , 0.62507019, 
       0.64991591, 0.67389356, 0.69694438, 0.71902138, 0.74008905, 
       0.76012273, 0.77910799, 0.79703987, 0.81392209, 0.82976609, 
       0.84459023, 0.85841887, 0.87128143, 0.88321163, 0.89424658, 
       0.90442608, 0.91379189, 0.92238706, 0.93025537, 0.93744079, 
       0.94398702, 0.94993712, 0.95533313, 0.96021585, 0.96462454, 
       0.96859684]) 

pl.scatter(a,b,color = "blue", marker = 'o', s = 20) 
pl.plot(aa, ss, 'r-') 

和我需要将其旋转，这样：

x轴应0-1（所以b）和y轴应该反向排序，如

a2 = sorted(a, reverse = True) 
aa2 = sorted(aa, reverse = True) 

所以基本上按顺时针方向旋转它并改变旋转图的X轴顺序。我最近的尝试是因为这样：

pl.scatter(b,a2,color = "blue", marker = 'o', s = 20) 
pl.plot(ss, aa2, 'r-') 

但逻辑didnt旋转，我想要的曲线。有任何想法吗？

我试了this后，但没有什么帮助。 pl.scatter似乎不必须orientation属性和scipy.ndimage retured我

File "C:\Users\rpaca\Desktop\WinPython-64bit-3.5.2.2\python-3.5.2.amd64\lib\site-packages\scipy\ndimage 
\interpolation.py", line 663, in rotate 
ix = input.shape[axes[1]] 
IndexError: tuple index out of range 

而且，在旋转的情节应该有更多的点，我会添加。所以我真的想通过改变曲线点的位置而不是使用任何模糊函数来做到这一点。我在winpython中使用python 3。

Answer 1

的旋转必须始终出现在左右空间中的点（我们称之为origin）。

要实现一个旋转，你需要将你的点移动到原点，旋转它们到一个选择的角度并将它们移回去。如果你的角度为90°，旋转是直线前进

x_new = -y 
y_new = x 

在这样的方式的图像可以旋转：

import numpy as np 
import matplotlib.pyplot as plt 

a = np.array([4, 4, 4, 4, 5, 5, 5, 6, 6, 6, 6, 6, 6, 6, 7, 7, 7, 8, 8, 8, 9]) 
b = np.array([i/float(len(a)) for i in range(1, len(a)+1)]) 
A = np.array([i/10. for i in range(40, 91)]) 
B = np.array([ 0.06200455, 0.07389492, 0.08721351, 0.10198928, 0.11823225, 
       0.13593267, 0.15506088, 0.1755675 , 0.19738431, 0.22042543, 
       0.244589 , 0.26975916, 0.29580827, 0.32259936, 0.34998862, 
       0.377828 , 0.40596767, 0.43425846, 0.46255411, 0.49071331, 
       0.51860153, 0.54609255, 0.57306977, 0.5994272 , 0.62507019, 
       0.64991591, 0.67389356, 0.69694438, 0.71902138, 0.74008905, 
       0.76012273, 0.77910799, 0.79703987, 0.81392209, 0.82976609, 
       0.84459023, 0.85841887, 0.87128143, 0.88321163, 0.89424658, 
       0.90442608, 0.91379189, 0.92238706, 0.93025537, 0.93744079, 
       0.94398702, 0.94993712, 0.95533313, 0.96021585, 0.96462454, 
       0.96859684]) 



def rotate(x,y, origin=(0,0)): 
    # shift to origin 
    x1 = x - origin[0] 
    y1 = y - origin[1] 

    #rotate 
    x2 = -y1 
    y2 = x1 

    # shift back 
    x3 = x2 + origin[1] 
    y3 = y2 + origin[0] 

    return x3, y3 

# now let's do the rotation 
origin = (9.,0.5) 
a1, b1 = rotate(a,b, origin) 
A1, B1 = rotate(A,B, origin) 


fig, (ax1, ax2) = plt.subplots(1,2, figsize=(7,3.3)) 

ax1.set_title("original") 
ax1.scatter(a, b, color = "blue", marker = 'o', s = 20) 
ax1.plot (A, B, 'r-') 

ax2.set_title(u"90° ccw rotated") 
ax2.scatter(a1, b1, color = "blue", marker = 'o', s = 20) 
ax2.plot (A1, B1, 'r-') 

plt.show() 

Answer 2

我可能会误解你的问题，但为什么不只是切换x和y轴的值？

pl.scatter(b,a,color = "blue", marker = 'o', s = 20) 
pl.plot(ss,aa, 'r-')