更多关于我的文字游戏的问题

Question

while(!A){ 
      System.out.println ("You enter a room and look around, in it, you see three  doors, a red door labeled A, a blue door labeled B, and a green door labeled C. Which door do you choose to go through? Enter, A, B, or C"); 
      String correctdoor = scanner.next(); 

      A = "A".equalsIgnoreCase(correctdoor); 
      System.out.println("You have chosen wrong! You have fallen into a pit! Lucky for you though, the pit is easy to climb out of and you return to the room....\n\n\n");   
     } 

    System.out.println("You progress through the door and find 5 light switches, you must turn them on in order to progress further. Enter the correct combination (using digits 1-5) here please. HINT - the 2nd and 4th numbers add up to the first number and the last number is NOT 5"); 
    int lightcode = scanner.nextInt(); 
    while (!(lightcode == 31425)){System.out.println ("That combination is incorrect");} 
    System.out.println ("The door unlocks and you go down a set of stairs"); 

嘿，回来再寻求更多帮助。

当用户输入b或c或任何其他值不是A时，while语句的工作方式是按预期工作，但是当它们放入A时，它会将它们带出while循环，但它仍然会打印出'您已选择错误'的字符串。我不知道为什么，但我确定你们可以告诉我为什么。

此外，如果我输入正确的数字，第二个循环完美工作，唯一的问题是，当我不这样做，它会告诉我'组合不正确'，但它不会打印一次，它会一直打印它并不会停止，它的无休止的。我做错了什么？

也许我应该使用if语句？呃......不......那不会循环......呃。

PS我知道我说的最后一个数字的心不是5，但衣衫将其固定后

Answer 1

我看着你的代码，并用此来了，它为我工作和固定您所描述的问题：

现在

while(!A) 
{ 
     System.out.println ("You enter a room and look around, in it, you see three  doors, a red door labeled A, a blue door labeled B, and a green door labeled C. Which door do you choose to go through? Enter, A, B, or C"); 
     String correctdoor = scanner.next(); 

     A = "A".equalsIgnoreCase(correctdoor); 

     if (!A) // Added this here, displays the message only if they chose the incorrect door 
     { 
      System.out.println("You have chosen wrong! You have fallen into a pit! Lucky for you though, the pit is easy to climb out of and you return to the room....\n\n\n"); 
     } 
} 

，第二部分，这里是我做的，这也是固定的，你所描述的问题：

int lightcode = 0; //Initialize lightcode to something incorrect here 
while (!(lightcode == 31425)) 
{ 
System.out.println("You progress through the door and find 5 light switches, you must turn them on in order to progress further. Enter the correct combination (using digits 1-5) here please. HINT - the 2nd and 4th numbers add up to the first number and the last number is NOT 5"); 
    lightcode = scanner.nextInt(); //Get lightcode from the player 

    if (!(lightcode == 31425)) //And finally, only if the code is INCORRECT, display the incorrect message 
    { 
    System.out.println ("That combination is incorrect"); 
    } 
} 

System.out.println ("The door unlocks and you go down a set of stairs"); 

Answer 2

好吧，这里就是我会做这样的：

while(true){ 
    System.out.println ("You enter a room and look around, in it, you see three  doors, a red door labeled A, a blue door labeled B, and a green door labeled C. Which door do you choose to go through? Enter, A, B, or C"); 
    String correctdoor = scanner.next(); 
    if("A".equalsIgnoreCase(correctdoor)) { 
    break; 
    } 
    System.out.println("You have chosen wrong! You have fallen into a pit! Lucky for you though, the pit is easy to climb out of and you return to the room....\n\n\n"); 
} 

我明白，intui！（lightcode == 31425）tively，在while循环中设置条件看起来像正确的路要走，但问题是，该条件是有用的，因为你有流量控制发生在while循环中。所以，我只是更加清楚地说明了这一点：永久循环，如果correctdoor匹配“A”，就会打破循环

对于你的第二个问题，你可以使用非常相同的方法，因为逻辑是一样的：永远循环直到你得到你的期望。

System.out.println("You progress through the door and find 5 light switches, you must turn them on in order to progress further. Enter the correct combination (using digits 1-5) here please. HINT - the 2nd and 4th numbers add up to the first number and the last number is NOT 5"); 
int lightcode = 0; 
while (true){ 
    lightcode = scanner.nextInt(); 
    if(lightcode == 31425) { 
    break; 
    } 
    System.out.println ("That combination is incorrect"); 
} 
    System.out.println ("The door unlocks and you go down a set of stairs"); 

如果你第一次要求每次重复键的声明，就把它放在第二个开始的时候。 祝你的游戏制作成功！ 为了以防万一，这里有我写的工作代码的要点 https://gist.github.com/dallarosa/14617052520c571ad2ad