如何比较两个字符串在SQL Server 2008的T-SQL中是否包含相同的单词？

declare @s1 varchar(50) = 'my word' 
declare @s2 varchar(50) = 'word my' 

declare @t1 table (word varchar(50)) 

while len(@s1)>0 
begin 
    if (CHARINDEX(' ', @s1)>0) 
    begin  
     insert into @t1 values(ltrim(rtrim(LEFT(@s1, charindex(' ', @s1)))))   
     set @s1 = LTRIM(rtrim(right(@s1, len(@s1)-charindex(' ', @s1)))) 
    end 
    else 
    begin 
     insert into @t1 values (@s1) 
     set @s1=''  
    end  
end 

declare @t2 table (word varchar(50)) 
while len(@s2)>0 
begin 
    if (CHARINDEX(' ', @s2)>0) 
    begin  
     insert into @t2 values(ltrim(rtrim(LEFT(@s2, charindex(' ', @s2)))))   
     set @s2 = LTRIM(rtrim(right(@s2, len(@s2)-charindex(' ', @s2)))) 
    end 
    else 
    begin 
     insert into @t2 values (@s2) 
     set @s2=''  
    end  
end 

select case when exists(SELECT * FROM @t1 EXCEPT SELECT * FROM @t2) then 'are not' else 'are equal' end

来源

2012-05-03 21:35:40 Taher

这不是单行查询的答案 – 2016-08-17 05:32:10

试试这个... StringSorter函数在空间上打断字符串，然后对所有单词进行排序，然后按照排序的单词顺序将字符串放回到一起。

CREATE FUNCTION dbo.StringSorter(@sep char(1), @s varchar(8000)) 
RETURNS varchar(8000) 
AS 
BEGIN 
    DECLARE @ResultVar varchar(8000); 

    WITH sorter_cte AS (
     SELECT CHARINDEX(@sep, @s) as pos, 0 as lastPos 
     UNION ALL 
     SELECT CHARINDEX(@sep, @s, pos + 1), pos 
     FROM sorter_cte 
     WHERE pos > 0 
    ) 
    , step2_cte AS (
    SELECT SUBSTRING(@s, lastPos + 1, 
      case when pos = 0 then 80000 
      else pos - lastPos -1 end) as chunk 
    FROM sorter_cte 
    ) 
    SELECT @ResultVar = (select ' ' + chunk 
            from step2_cte 
            order by chunk 
            FOR XML PATH('')); 
    RETURN @ResultVar; 
END 
GO

下面是一个测试用例只是想出来的功能：

SELECT dbo.StringSorter(' ', 'the quick brown dog jumped over the lazy fox');

其产生这些结果：

brown dog fox jumped lazy over quick the the

然后从SELECT语句中使用字符串运行

SELECT case when dbo.StringSorter(' ', 'my word') = 
        dbo.StringSorter(' ', 'word my') 
       then 'Equal' else 'Not Equal' end as ResultCheck 
SELECT case when dbo.StringSorter(' ', 'my word') = 
        dbo.StringSorter(' ', 'aaamy word') 
       then 'Equal' else 'Not Equal' end as ResultCheck

第一次e表明他们是平等的，而第二个则没有。

这应该做你正在寻找与一个简单的函数利用递归CTE排序你的字符串。

享受！

来源

2012-05-04 00:56:16

一个非常简单的方法来做到这一点... JC65100

ALTER FUNCTION [dbo].[ITS_GetDifCharCount] 
(
@str1 VARCHAR(MAX) 
,@str2 VARCHAR(MAX) 
) 
RETURNS INT 
AS 
BEGIN 
DECLARE @result INT 

SELECT @result = COUNT(*) 
FROM dbo.ITS_CompareStrs(@str1,@str2) 

RETURN @result 

END 


ALTER FUNCTION [dbo].[ITS_CompareStrs] 
(
@str1 VARCHAR(MAX) 
,@str2 VARCHAR(MAX) 
) 
RETURNS 
@Result TABLE (ind INT, c1 char(1), c2 char(1)) 
AS 
BEGIN 
    DECLARE @i AS INT 
      ,@c1 CHAR(1) 
      ,@c2 CHAR(1) 

    SET @i = 1 

    WHILE LEN (@str1) > @i-1 OR LEN (@str2) > @i-1 
    BEGIN 

     IF LEN (@str1) > @i-1 
     SET @c1 = substring(@str1, @i, 1) 

     IF LEN (@str2) > @i-1 
     SET @c2 = substring(@str2, @i, 1) 

     INSERT INTO @Result([ind],c1,c2) 
     SELECT @i,@c1,@c2 

     SELECT @[email protected]+1 
       ,@c1=NULL 
       ,@c2=NULL 

    END 

    DELETE FROM @Result 
    WHERE c1=c2 


RETURN 
END

来源

2012-11-06 19:00:16 JorgeC

如何比较两个字符串在SQL Server 2008的T-SQL中是否包含相同的单词？

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