我有2个表中的行:加入MySQL中2个表,返回不相关
表1:问题(ID,问题,日期)
表2:答案(ID,question_id,答案,日期)
一个问题可以有1个以上的答案,有些问题没有答案。我想只输出悬而未决的问题
像SELECT * FROM
问题,
答案查询WHERE questions.id!=answers.question_id group by questions.id
不起作用
有人能帮助新手喜欢我,我很迷失在这一切MySQL的东西。
我有2个表中的行:加入MySQL中2个表,返回不相关
表1:问题(ID,问题,日期)
表2:答案(ID,question_id,答案,日期)
一个问题可以有1个以上的答案,有些问题没有答案。我想只输出悬而未决的问题
像SELECT * FROM
问题,
答案查询WHERE questions.id!=answers.question_id group by questions.id
不起作用
有人能帮助新手喜欢我,我很迷失在这一切MySQL的东西。
SELECT id, question, date
FROM questions q
WHERE NOT EXISTS
(SELECT * FROM answers a
WHERE a.question_id = q.id)
OR
SELECT id, question, date
FROM questions q
LEFT JOIN answers a ON a.question_id = q.id
WHERE a.id IS NULL
OR
SELECT id, question, date
FROM questions q
WHERE q.id NOT IN
(SELECT question_id FROM answers WHERE question_id IS NOT NULL)
/* If question_id can't be NULL this is not needed*/
SELECT Q.id, Q.question, Q.date
FROM questions Q LEFT JOIN answers A ON (Q.id = A.question_id)
WHERE A.id IS NULL
SELECT * FROM 问题,答案 WHERE answers.answer = null或answers.answer = “”;
谢谢。没想到会这么快。再次感谢你,它的工作原理。爱MySQL – olegb 2010-07-08 15:49:56