如何加入PHP 2个MySQL查询作为hetml返回值

Indivudually这些查询运行100％如何加入PHP 2个MySQL查询作为hetml返回值

QUERY1

SELECT year_entered, 
    month_entered, 
    IFNULL(amount - @n, 0) amount_diff, 
    @n := amount current_amount 
    FROM 
(SELECT YEAR(date_entered) year_entered, 
    MONTHNAME(date_entered) month_entered, 
    SUM(amount) amount 
FROM opportunities 
INNER JOIN opportunities_cstm 
ON (opportunities.id = opportunities_cstm.id_c) 
WHERE 
YEAR(opportunities.date_entered) >= YEAR(CURDATE()) 
AND (`opportunities`.`deleted` <> '1') AND 
(opportunities_cstm.interest_level_c = 'Ultraspin' 
OR 
opportunities_cstm.interest_level_c = 'Mycelx') 
GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
(SELECT @n := NULL) n

查询2

SELECT year_entered, 
    month_entered, 
    IFNULL(id - @n, 0) id_diff, 
     @n := id current_id 
    FROM 
(SELECT YEAR(date_entered) year_entered, 
     MONTHNAME(date_entered) month_entered, 
     COUNT(id) id 
    FROM opportunities 
    INNER JOIN opportunities_cstm 
    ON (opportunities.id = opportunities_cstm.id_c) 
WHERE 
YEAR(opportunities.date_entered) >= YEAR(CURDATE()) 
AND (`opportunities`.`deleted` <> '1') AND 
(opportunities_cstm.interest_level_c = 'Ultraspin' 
OR 
opportunities_cstm.interest_level_c = 'Mycelx') 
    GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
(SELECT @n := NULL) n 
ON year_entered = year_entered

我需要怎么量的差异和在一个查询计数差异，想要用户贾斯珀报告来报告这一点，或者如果有人可以帮助PHP返回行？

只是不知道如何在查询和返回旁边它们彼此

来源

2013-05-06 Paul van Zyl

试试这个：

SELECT year_entered, 
    month_entered, 
    query1.amount_diff, 
    query2.id_diff FROM 
     (SELECT year_entered, 
      month_entered, 
      IFNULL(amount - @n, 0) amount_diff, 
      @n := amount current_amount 
      FROM 
     (SELECT YEAR(date_entered) year_entered, 
      MONTHNAME(date_entered) month_entered, 
      SUM(amount) amount 
     FROM opportunities 
     INNER JOIN opportunities_cstm 
     ON (opportunities.id = opportunities_cstm.id_c) 
     WHERE 
     YEAR(opportunities.date_entered) >= YEAR(CURDATE()) 
     AND (`opportunities`.`deleted` <> '1') AND 
     (opportunities_cstm.interest_level_c = 'Ultraspin' 
     OR 
     opportunities_cstm.interest_level_c = 'Mycelx') 
     GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
     (SELECT @n := NULL) n) query1 JOIN (
      SELECT year_entered, 
       month_entered, 
       IFNULL(id - @n, 0) id_diff, 
        @n := id current_id 
       FROM 
      (SELECT YEAR(date_entered) year_entered, 
        MONTHNAME(date_entered) month_entered, 
        COUNT(id) id 
       FROM opportunities 
       INNER JOIN opportunities_cstm 
       ON (opportunities.id = opportunities_cstm.id_c) 
      WHERE 
      YEAR(opportunities.date_entered) >= YEAR(CURDATE()) 
      AND (`opportunities`.`deleted` <> '1') AND 
      (opportunities_cstm.interest_level_c = 'Ultraspin' 
      OR 
      opportunities_cstm.interest_level_c = 'Mycelx') 
       GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
      (SELECT @n := NULL) n 
      ON year_entered = year_entered 
     ) query2 ON query1.year_entered = query2.year_entered AND query1.month_entered = query2.month_entered

来源

2013-05-06 14:28:24

SELECT year_entered, 
     month_entered, 
     IFNULL(amount - @n, 0) amount_diff, 
     IFNULL(id - @a, 0) id_diff, 
     @n := amount current_amount, 
     @i := id current_id 
FROM (SELECT YEAR(date_entered) year_entered, 
      MONTHNAME(date_entered) month_entered, 
      SUM(amount) amount, 
      COUNT(id) id 
     FROM opportunities 
     INNER JOIN opportunities_cstm 
     ON (opportunities.id = opportunities_cstm.id_c) 
     WHERE YEAR(opportunities.date_entered) >= YEAR(CURDATE()) 
      AND (`opportunities`.`deleted` <> '1') 
      AND (opportunities_cstm.interest_level_c = 'Ultraspin' 
      OR opportunities_cstm.interest_level_c = 'Mycelx') 
     GROUP BY YEAR(date_entered), MONTH(date_entered)) q, 
    (SELECT @n := NULL, @i := NULL) n

来源

2013-05-06 14:31:49 Barmar

如何加入PHP 2个MySQL查询作为hetml返回值

回答

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