javax.xml.transform.Transformer忽略前缀？

Question

我试图解析一个很简单的例子：

<?xml version="1.0" encoding="UTF-8"?> 
<root xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'> 
    <openSearch:totalResults>100</openSearch:totalResults> 
</root> 

我使用的样式表如下：

<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" 
       version="1.0" 
       xmlns:app='http://www.w3.org/2007/app' > 
<xsl:output method="xml" indent="yes"/> 
<xsl:preserve-space elements="*"/> 
<xsl:template match="/"> 
    <results> 
     <xsl:attribute name="total-results"> 
       <xsl:value-of 
       select="atom:root/openSearch:totalResults"/> 
     </xsl:attribute> 
    </results> 
</xsl:template> 
</xsl:stylesheet> 

这工作在的libxslt，没有问题。我正试图在java中执行相同的任务，并且正在尝试使用javax.xml.transform包来执行此操作。它不是预期的结果，它为总结果属性提供了一个空值。但是，当我改变这个值：

   <xsl:value-of select="root/totalResults"/> 

它的工作原理。更改xml和xslt不是一个选项。有一个参数我应该设置在某个地方？代码非常简单：

InputSource xmlSource = new InputSource(new StringReader(xml)); 

DocumentBuilder builder = factory.newDocumentBuilder(); 
document = builder.parse(xmlSource); 

// Use a Transformer for output 
TransformerFactory tFactory = TransformerFactory.newInstance(); 


StreamSource stylesource = new StreamSource(new StringReader(styleSheet)); 
Transformer transformer = tFactory.newTransformer(stylesource); 

StringWriter writer = new StringWriter(); 

DOMSource source = new DOMSource(document); 
StreamResult result = new StreamResult(writer); 
transformer.transform(source, result); 

stringResult = writer.toString(); 

Answer 1

在样式表中，您缺少“atom”和“openSearch”的名称空间声明。 以下工作：

1. 添加了“OpenSearch的”命名空间（从XML复制）在样式表
2. 删除了“原子”命名空间，因为有
3. 将工厂作为本 名字空间中没有信息命名空间意识到：factory.setNamespaceAware(true);

这里是Scala的完整代码（对不起，我是懒得解析该文件中的XML和样式表或在Java中做字符串连接）：

def testxsl = { 
     val xml = """<?xml version="1.0" encoding="UTF-8"?> 
<root xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'> 
    <openSearch:totalResults>100</openSearch:totalResults> 
</root> 
     """ 
     val styleSheet = """<?xml version="1.0" encoding="UTF-8"?> 
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0" 
     xmlns:app='http://www.w3.org/2007/app' 
     xmlns:openSearch='http://a9.com/-/spec/opensearch/1.1/'> 
<xsl:output method="xml" indent="yes"/> 
<xsl:preserve-space elements="*"/> 
<xsl:template match="/"> 
    <results> 
     <xsl:attribute name="total-results"> 
       <xsl:value-of select="root/openSearch:totalResults"/> 
     </xsl:attribute> 
    </results> 
</xsl:template> 
</xsl:stylesheet> 
     """ 
    val xmlSource = new InputSource(new StringReader(xml)); 
    val factory = DocumentBuilderFactory.newInstance(); 
    factory.setNamespaceAware(true); 
    val builder = factory.newDocumentBuilder(); 
    val document = builder.parse(xmlSource); 

    // Use a Transformer for output 
    val tFactory = TransformerFactory.newInstance(); 


    val stylesource = new StreamSource(new StringReader(styleSheet)); 
    val transformer = tFactory.newTransformer(stylesource); 

    val writer = new StringWriter(); 

    val source = new DOMSource(document); 
    val result = new StreamResult(writer); 
    transformer.transform(source, result); 
    writer.toString(); 
    }