您可以使用拆分功能......尽管您的值不应该像这样存储在第一位。
declare @table table (col1 varchar(256))
insert into @table
values
('Value1 - Value2: Value3 - Value4: Value5 - Value6:')
select
ReturnVal = replace(ltrim(left(Item,charindex('-',Item))),'-',':')
from
@table
cross apply dbo.DelimitedSplit8K(col1,':')
where
Item <> ''
退货
+-----------+
| ReturnVal |
+-----------+
| Value1 : |
| Value3 : |
| Value5 : |
+-----------+
或者,一个丑陋的黑客攻击拿回来你想要的
select distinct
--ReturnVal = replace(ltrim(left(Item,charindex('-',Item))),'-',':')
ReturnVal = 'V' + STUFF((
SELECT replace(left(Item,charindex('-',Item)),'-',':')
FROM
@table
cross apply dbo.DelimitedSplit8K(col1,':')
FOR XML PATH(''), TYPE).value('.', 'NVARCHAR(MAX)'), 1, 1, '')
from
@table
cross apply dbo.DelimitedSplit8K(col1,':')
where
Item <> ''
退货
ReturnVal
Value1 : Value3 : Value5 :
JEFF MODEN SPLITTER
CREATE FUNCTION [dbo].[DelimitedSplit8K] (@pString VARCHAR(8000), @pDelimiter CHAR(1))
--WARNING!!! DO NOT USE MAX DATA-TYPES HERE! IT WILL KILL PERFORMANCE!
RETURNS TABLE WITH SCHEMABINDING AS
RETURN
/* "Inline" CTE Driven "Tally Table" produces values from 1 up to 10,000...
enough to cover VARCHAR(8000)*/
WITH E1(N) AS (
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL
SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1 UNION ALL SELECT 1
), --10E+1 or 10 rows
E2(N) AS (SELECT 1 FROM E1 a, E1 b), --10E+2 or 100 rows
E4(N) AS (SELECT 1 FROM E2 a, E2 b), --10E+4 or 10,000 rows max
cteTally(N) AS (--==== This provides the "base" CTE and limits the number of rows right up front
-- for both a performance gain and prevention of accidental "overruns"
SELECT TOP (ISNULL(DATALENGTH(@pString),0)) ROW_NUMBER() OVER (ORDER BY (SELECT NULL)) FROM E4
),
cteStart(N1) AS (--==== This returns N+1 (starting position of each "element" just once for each delimiter)
SELECT 1 UNION ALL
SELECT t.N+1 FROM cteTally t WHERE SUBSTRING(@pString,t.N,1) = @pDelimiter
),
cteLen(N1,L1) AS(--==== Return start and length (for use in substring)
SELECT s.N1,
ISNULL(NULLIF(CHARINDEX(@pDelimiter,@pString,s.N1),0)-s.N1,8000)
FROM cteStart s
)
--===== Do the actual split. The ISNULL/NULLIF combo handles the length for the final element when no delimiter is found.
SELECT ItemNumber = ROW_NUMBER() OVER(ORDER BY l.N1),
Item = SUBSTRING(@pString, l.N1, l.L1)
FROM cteLen l
;
GO
在开始之前,它看起来像执行非常差在单个列使用文本EAV'的'。我强烈建议停止并规范您的模式。或者至少使用某种类型的结构化数据,比如'XML' /'JSON' – lad2025
您应该修复数据模型,使每个实体有一行,每个值在单独的行中。如果你不能这样做,你应该解释为什么你要在一个字符串中存储多个值 - 这不是存储数据的SQLish方式。 –
请考虑重构您的数据库。这是一个糟糕的设计。 阅读[在数据库列中存储分隔列表真的不好吗?](http://stackoverflow.com/questions/3653462/is-storing-a-delimited-list-in-a-database-column-really-那么 - 坏),在那里你会看到很多原因,为什么这个问题的答案是**绝对是!** –