PHP - 格式错误

我目前正在通过PHP教科书创建电影评论网站，但是，我创建的页面格式不正确，我无法看到我的代码与代码之间的区别教科书。以下是我创建的页面的屏幕截图： http://imgur.com/a/EBNxk PHP - 格式错误

“Date”应该是“Reviewer”，“Comments”和“Rating”旁边的表格标题。 “评论”标题也意味着低于电影细节以及“日期”，“评论者”，“评论”和“评级”之上。该页面的完整代码包含在下面，我知道这个问题可能会在html标签之间出现，但我会把它全部包含在内。

编辑：我现在看到我在130行上留下了一个引号。解决这个问题将“日期”与其他标题一起放置，因为它应该是。但评论标题仍然在电影细节之上。

<?php 
function get_director($director_id) 
{ 
    global $db; 
    $query = "SELECT people_fullname FROM people WHERE people_id = ". $director_id; 
    $result = mysqli_query($db,$query) or die(mysqli_error($db)); 
    $row = mysqli_fetch_assoc($result); 
    extract($row); 
    return $people_fullname; 
} 

function get_leadactor($leadactor_id) 
{ 
    global $db; 
    $query = "SELECT people_fullname FROM people WHERE people_id = ". $leadactor_id; 
    $result = mysqli_query($db,$query) or die(mysqli_error($db)); 
    $row = mysqli_fetch_assoc($result); 
    extract($row); 
    return $people_fullname; 
} 

function get_movietype($type_id) 
{ 
    global $db; 
    $query = "SELECT movietype_label FROM movietype WHERE movietype_id = ". $type_id; 
    $result = mysqli_query($db,$query) or die(mysqli_error($db)); 
    $row = mysqli_fetch_assoc($result); 
    extract($row); 
    return $movietype_label; 
} 

function generate_stars($rating) 
{ 
    $stars = " "; 
    for($i = 0; $i <= $rating; $i++) 
    { 
     $stars.= '<img src = "star.png" alt = "star " />'; 
    } 
    return $stars; 
} 

function calculate_difference($takings,$cost) 
{ 
    $difference = $takings - $cost; 

    if($difference<0) 
    { 
     $color = "red"; 
     $difference = "$ ".abs($difference)." million"; 
    } 
    else if ($difference > 0) 
    { 
     $color = "green"; 
     $difference = "$ ".abs($difference)." million"; 
    } 
    else 
    { 
     $color = "blue"; 
     $difference = "$ ".abs($difference)." million"; 
    } 

    return "<span style = \"color:".$color.";\">".$difference."</span>"; 
} 

$db = mysqli_connect('localhost','root') or die('Unable to connect'); 
mysqli_select_db($db,'moviesite') or die (mysqli_error($db)); 

$query = "SELECT movie_name, movie_year, movie_director, movie_leadactor, 
      movie_type, movie_running_time, movie_cost, movie_takings 
      FROM movie 
      WHERE movie_id = ".$_GET["movie_id"]; 
$result = mysqli_query($db,$query); 
$row = mysqli_fetch_assoc($result); 

$movie_name = $row['movie_name']; 
$movie_director = get_director($row['movie_director']); 
$movie_leadactor = get_leadactor($row['movie_leadactor']); 
$movie_year = $row['movie_year']; 
$movie_running_time = $row['movie_running_time']." mins"; 
$movie_takings = $row['movie_takings']." million"; 
$movie_cost = $row['movie_cost']." million"; 
$movie_health = calculate_difference($row['movie_takings'],$row['movie_cost']); 

echo <<<ENDHTML 
<html> 
    <head> 
    <title> Details for $movie_name </title> 
    </head> 

    <body> 
    <div style = "text-align:center"> 
    <h2> $movie_name </h2> 
    <h3> Details </h3> 
    <table cellpadding = "2" cellspacing = "2" style = "width:70%; margin-left:auto; margin-right:auto"> 
     <tr> 
      <td> <strong> Title </strong></td> 
      <td> $movie_name </td> 
      <td> <strong> Release Year </strong></td> 
      <td> $movie_year </td> 
     </tr> 
     <tr> 
      <td> <strong> Movie Director </strong></td> 
      <td> $movie_director </td> 
      <td> <strong> Cost </strong></td> 
      <td> $movie_cost </td> 
     </tr> 
     <tr> 
      <td> <strong> Lead Actor </strong></td> 
      <td> $movie_leadactor </td> 
      <td> <strong> Takings </strong></td> 
      <td> $movie_takings </td> 
     </tr> 
     <tr> 
      <td> <strong> Running Time </strong></td> 
      <td> $movie_running_time </td> 
      <td> <strong> Health </strong></td> 
      <td> $movie_health </td> 
     </tr> 
ENDHTML; 

$query = 'SELECT review_movie_id, review_date, reviewer_name, review_comment, review_rating 
      FROM reviews 
      WHERE review_movie_id = '.$_GET['movie_id'] . ' 
      ORDER BY review_date DESC'; 
$result = mysqli_query($db, $query) or die(mysqli_error($db)); 

echo <<<ENDHTML 
<h3><em>Reviews</em></h3> 
<table cellpadding = "2" cellspacing = "2" 
    style = "width:90%; margin-left:auto; margin-right:auto;> 
    <tr> 
     <th style = "width: 7em"> Date </th> 
     <th style = "width: 10em"> Reviewer </th> 
     <th> Comments </th> 
     <th style = "width: 5em"> Rating </th> 
    </tr> 
</table> 
ENDHTML; 

while($row = mysqli_fetch_assoc($result)) 
{ 
    $date = $row['review_date']; 
    $name = $row['reviewer_name']; 
    $comment = $row['review_comment']; 
    $rating = generate_stars($row['review_rating']); 

    echo <<<ENDHTML 
    <td style = "vertical-align: top; text-align:center"> $date </td> 
    <td style = "vertical-align: top; text-align:center"> $name </td> 
    <td style = "vertical-align: top; text-align:center"> $comment </td> 
    <td style = "vertical-align: top; text-align:center"> $rating </td> 
    <br/> 
ENDHTML; 

} 

echo <<< ENDHTML 

    </div> 
    </body> 
</html> 


ENDHTML; 

?>

来源

2016-07-28 max2015

你应该有'每个审核tr's。我猜想的星星问题是一个图像位置问题？检查你的开发者控制台 – chris85

这也适用于SQL注入。您应该使用mysqli预准备语句来使用参数化查询。 – chris85

请尝试关闭款式引号：

<table cellpadding = "2" cellspacing = "2" style = "width:90%; margin-left:auto; margin-right:auto;"> 
<tr> 
    <th style = "width: 7em"> Date </th>

来源

2016-07-28 12:45:16 Janno

PHP - 格式错误

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