试图写一个接触的形式脚本只是我的下页心不是处理...联系表格错误PHP
<?php
$rpname = $_POST['name'];
$rpnumber = $_POST['phone'];
echo $rpname;
echo $rpnumber;
$rpname = $_POST['name'];
$rpnumber = $_POST['phone'];
$to = "[email protected]"; // CHANGE THIS TO EMAIL YOU WANT
$subject = "Phonecall Request"
//begin of HTML message
$message = "
Phone call request -
From : $rpname,
Number: $rpnumber
";
$headers = "MIME-Version: 1.0rn";
$headers .= "Content-type: text/html; charset=iso-8859-1rn";
$headers .= "From: Website Enquiry";
if (isset($rpname))
{
// now lets send the email.
mail($to, $subject, $message, $headers);
$page='index.html';
header('Location:'.$page);
header('Location: ' . $_SERVER['HTTP_REFERER'] . '?e=Message Sent!');
} ?>
我用尽呼应顶部得到一个空白页,没有源变量,但即时通讯.. 。
在脚本的开始处添加这个错误,并报告错误,您将收到error_reporting(E_ALL); ini_set('display_errors','1');' – nicky77 2012-01-08 20:27:33
也尝试print_r($ _ POST);在顶部,打印出阵列 – 2012-01-08 20:28:01