Python - 用matplotlib组织3个子图

Question

我尝试为我的图形生成3个子图。它似乎工作，但它并不完全一致。如何在底部的图形和下面的图形之间有相同的宽度？

plt.close() 
fig = plt.figure() 

ax1 = plt.subplot(211) 
ax1.plot(cycles,np.asarray(df_int),'wo',label='') 
ax1.plot(cycles,np.asarray(df_proj),'k+',label='') 
ax1.legend(loc=2) 
#ax1.subplots_adjust(left=0.15) 
ax1.set_ylim(0.001,0.004) 

ax2 = plt.subplot(223) 
i2=ax2.imshow(c,cmap=plt.cm.hot, vmin=-5, vmax=5);#plt.colorbar();plt.clim(-5,5) 
cb2=plt.colorbar(i2,ax=ax2,ticks=[-5,0,5],fraction=0.046, pad=0.04,format='%.2f') 
cb2.ax.tick_params(labelsize=12) 



ax3 = plt.subplot(224) 
i3=ax3.imshow(residue_proj,cmap=plt.cm.hot, vmin=-5, vmax=5);#plt.colorbar();plt.clim(-5,5); 
cb3=plt.colorbar(i3,ax=ax3,ticks=[-5,0,5],fraction=0.046, pad=0.04,format='%.2f') 
cb3.ax.tick_params(labelsize=12) 

plt.savefig('test.png', dpi=500, bbox_inches='tight', pad_inches=0.1) 
#plt.show() 

Answer 1

这可能是一个容易得多，如果你使用GridSpec：

import numpy as np 
import matplotlib.pylab as pl 
import matplotlib.gridspec as gridspec 

# Create 2x2 sub plots 
gs = gridspec.GridSpec(2, 2) 

pl.figure() 
ax = pl.subplot(gs[0, 0]) # row 0, col 0 
pl.plot([0,1]) 

ax = pl.subplot(gs[0, 1]) # row 0, col 1 
pl.plot([0,1]) 

ax = pl.subplot(gs[1, :]) # row 1, span all columns 
pl.plot([0,1]) 

参见：http://matplotlib.org/users/gridspec.html

Answer 2

同为上面的回答可以是用figu完成像这样对象：

import matplotlib.pyplot as plt 
import matplotlib.gridspec as gridspec 

# Create 2x2 sub plots 
gs = gridspec.GridSpec(2, 2) 

fig = plt.figure() 
ax1 = fig.add_subplot(gs[0, 0]) # row 0, col 0 
ax1.plot([0,1]) 

ax2 = fig.add_subplot(gs[0, 1]) # row 0, col 1 
ax2.plot([0,1]) 

ax3 = fig.add_subplot(gs[1, :]) # row 1, span all columns 
ax3.plot([0,1])