我正在VS2012中使用NSubstitute进行测试,并试图将模型转换为列表,或者我可以计算的东西。下面的代码:在MVC测试中将模型转换为列表
[TestMethod]
public void StartedGame()
{
// arrange
var repo = Substitute.For<IGameRepository>();
IEnumerable<Game> expectedGames = new List<Game>
{
new Game{ gameTypeID = 1, hasStarted = false, ID = 1, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 1, hasStarted = false, ID = 2, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 2, hasStarted = false, ID = 3, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 2, hasStarted = false, ID = 4, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 1, hasStarted = false, ID = 5, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false}
};
repo.GetGames().Returns(expectedGames);
var sut = new GameController(repo);
// act
var actual = sut.GameMenuStart();
// assert
//Assert.IsInstanceOfType(actual, typeof(ViewResult));
var viewResult = actual as ViewResult;
Assert.IsNotNull(viewResult);
}
当我调试,我可以将鼠标悬停在“的ViewResult”看型号,有我看到的条目与“计数”,但我怎么能达到呢?我试图铸造“游戏”的对象,像这样:
Game[] theModel = (Game[])viewResult.Model;
并列出多,但总是失败。 任何想法?
编辑:的ViewResult的类型为:System.Web.Mvc.ViewResult
下面是代码的这个函数内的其余部分:
var repo = Substitute.For<IGameRepository>();
IEnumerable<Game> expectedGames = new List<Game>
{
new Game{ gameTypeID = 1, hasStarted = false, ID = 1, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 1, hasStarted = false, ID = 2, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 2, hasStarted = false, ID = 3, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 2, hasStarted = false, ID = 4, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false},
new Game{ gameTypeID = 1, hasStarted = false, ID = 5, isOver = false, isPublic = true, maxPlayers = 2, someoneReported = false}
};
repo.GetGames().Returns(expectedGames);
var sut = new GameController(repo);
我已经添加了更多,以及viewResult的类型。它不包含'ToArray()'扩展名。 – Mappan 2013-05-14 17:43:02