火力IOS聊天应用程序无法正常工作

Question

我有了消息登录的用户的列表已经与他/她选择的任何用户有一个tableViewController。单击单元格时，它应该转到一个视图控制器，允许登录用户与任何用户聊天。我已经建立了一个覆盖赛格瑞：

var userpicuid: String? 
var username: String? 

override func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) { 

     let message = messages[indexPath.row] 

     if message.ReceiverId != self.loggedInUserUid { 
      var newVariable = message.ReceiverId 

      if self.userpicuid == newVariable { 

       let ref = FIRDatabase.database().reference().child("users").child(userpicuid!) 

       ref.observeSingleEvent(of: .value, with: { (snapshot) 
        in 

        if let dictionary = snapshot.value as? [String: AnyObject]{ 
         for post in dictionary { 
          let messages = post.value as! [String: AnyObject] 
          for (id, value) in messages { 

           self.username = messages["username"] as? String 


          }}}})}} else if message.senderId != self.loggedInUserUid { 
      let newVariable = message.senderId 

      if self.userpicuid == newVariable { 

       let ref = FIRDatabase.database().reference().child("users").child(userpicuid!) 

       ref.observeSingleEvent(of: .value, with: { (snapshot) 
        in 

        if let dictionary = snapshot.value as? [String: AnyObject]{ 
         for post in dictionary { 
          let messages = post.value as! [String: AnyObject] 
          for (id, value) in messages { 

           self.username = messages["username"] as? String 
          }}}})} 

     } 

    performSegue(withIdentifier: "MessageNow", sender: self.userpicuid) 

} 


override public func prepare(for segue: UIStoryboardSegue, sender: Any?) { 
    guard segue.identifier == "MessageNow", let chatVc = segue.destination as? SendMessageViewController else { 
     return 
    } 

    chatVc.senderId = self.loggedInUser?.uid 
    chatVc.receiverData = sender as AnyObject 
    chatVc.senderDisplayName = self.userpicuid 
    chatVc.username = self.username 

} 

而在目标视图控制器，这是设置：

var receiverData: AnyObject? 

override func viewDidLoad() { 
     super.viewDidLoad() 

     self.senderId = FIRAuth.auth()?.currentUser?.uid 

let receiverId = receiverData as! String 
     let receiverIdFive = String(receiverId.characters.prefix(5)) 
     let senderIdFive = String(senderId.characters.prefix(5)) 
     if (senderIdFive > receiverIdFive) 
     { 
      self.convoId = senderIdFive + receiverIdFive 
     } 
     else 
     { 
      self.convoId = receiverIdFive + senderIdFive 
     }} 

我得到的错误无法投类型的值“Lit_Swap.MessageTableViewCell”（ 0x1091d0f10）到'NSString'（0x10b153c60）。因为发件人显然是一个tableviewcell，我将如何设置发件人，这样我就可以点击该单元格并进入聊天控制器。

Answer 1

有很多的方法来视图之间移动数据，一个是赛格瑞并有许多用于segue'ing以及选项。

下面是一个使用representedObject财产

假设我们有一个文本框，并触发secondSheetController

class ViewController: NSViewController { 

    @IBOutlet weak var sourceTextField: UITextField! 

    override func viewDidLoad() { 
     super.viewDidLoad() 
    } 

    override func prepare(for segue: NSStoryboardSegue, sender: Any?) { 
     let second = segue.destinationController as! SecondController 
     second.representedObject = self.myTextField.text 
    } 
} 

而且我们segue'ing到

的的viewController的动作的按钮视图控制器一个

class SecondController: NSViewController { 

    @IBOutlet weak var targetTextField: NSTextField! 

    override func viewDidLoad() { 
     super.viewDidLoad() 
    } 

    override func viewWillAppear() { 
     self.targetTextField.text = self.representedObject as! String 
    } 
} 

另外，为了解决发送者是否是String的问题，我们不想使用representObject属性，分配给字符串将是一个解决方案。

chatVc.receiverData = sender as! String 

作为第三个选择，任何类在SecondController瓦尔可能是如果使用一个UINavigatorcontroll直接设置

class SecondController: NSViewController { 
    var option1 = "" 
    var option2 = "" 

然后从第一视图控制器

secondController.option1 = "look kids, Parliament, Big Ben" 
secondController.option2 = "Don't call me Shirley" 

Answer 2

。你可以试试这个解决方案。

func tableView(_ tableView: UITableView, didSelectRowAt indexPath: IndexPath) { 

    let selectedConversation = conversationArray[indexPath.row] 
    showConversationMessages(conversation: selectedConversation) 
} 


func showConversationMessages(conversation: ConversationItem){ 
    let vc = storyboard?.instantiateViewController(withIdentifier: "MessagesViewController") as! MessagesVC 
    vc.receiverId = conversation.idMessagePartner 
    vc.receiverToken = conversation.receiverToken 
    vc.receiverUserName = conversation.userDisplayName 
    navigationController?.pushViewController(vc, animated: true) 
} 

ConversationItem是我的课，用于存放我需要的数据。

然后你可以使用这些变量在你我已经在我的例子名为MessageVC第二控制器。

class MessagesVC: UIViewController, UITableViewDelegate, UITableViewDataSource, UITextViewDelegate { 
    private let TAG = "MessagesVC" 

    var receiverId: Int64 = 0 
    var receiverToken: String = "" 
    var receiverUserName: String = "" 

    .... 

我从来没有真正与override func prepare(for segue: NSStoryboardSegue, sender: Any?)合作过，但我确实看到很多有问题的人。