subprocess.Popen for循环输出

Question

代码：

with open ('Client.txt','r') as Client_Name: 
    for Client in Client_Name: 
     out = subprocess.Popen(['script.sh', '-byclient', Client], stdout=subprocess.PIPE) 
     outputstring = out.communicate() 
     print (outputstring) 

这个代码不给输出，我想在Client.txt文件传递客户端名称script.sh。任何建议请。

Answer 1

您的代码将名称传递给脚本似乎是正确的，但communicate实际上返回tuple,(stdout_data, stderr_data)。

您可能还想通过universal_newlines=True到Popen来解码输出。在CLIENT_NAME客户 ：试试这个：

out = subprocess.Popen(['script.sh', '-byclient', Client], 
         stdout=subprocess.PIPE, 
         universal_newlines=True) 
out.wait() # wait until the script has finished 
stdout_data, stderr_data = out.communicate() 
print(stdout_data) 

或者，如果你想实时打印输出：

out = subprocess.Popen(['script.sh', '-byclient', Client], 
         stdout=subprocess.PIPE, 
         universal_newlines=True) 
for line in out.stdout: 
    print(line)