2009-08-24 36 views

回答

3

我认为这应该工作(未经测试):

select artist_id, category, count(*) as total from table group by artist_id, category 
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感谢伯尔尼..它的工作.. – Fero 2009-08-24 06:56:14

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高兴能帮上忙 – bernhardrusch 2009-08-24 08:08:56

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