如何获得由PHP中包含PREPARE和EXECUTE的SQL查询返回的行？

Question

你如何使用PHP通过this SQL query返回该行：

SET @r := (SELECT ROUND(RAND() * (SELECT COUNT(*) FROM mytable))); 
SET @sql := CONCAT('SELECT * FROM mytable LIMIT ', @r, ', 1'); 
PREPARE stmt1 FROM @sql; 
EXECUTE stmt1; 

设置$query等于以上，然后做平常mysql_query($query)是不返回任何结果。

Answer 1

像这样做，看看它是否工作

mysql_query('SET @r := (SELECT ROUND(RAND() * (SELECT COUNT(*) FROM mytable)));'); 
mysql_query('SET @sql := CONCAT('SELECT * FROM mytable LIMIT ', @r, ', 1');'); 
$resource = mysql_query('PREPARE stmt1 FROM @sql;EXECUTE stmt1;'); 

不要忘记逃跑的SQL的第二个指令