我需要找到一种方法,找到一种方法,找到了在该XML节点编码数据以base64哈希//注意/资源/数据,或以某种方式相匹配,否则它在节点中的散列值//注意/内容/ EN-注// EN-媒体@散XSLT:获取或匹配的base64编码的哈希值数据
请参见下面的完整的XML文件
请建议的方式来获得{ |匹配} 使用XSLT
4aaafc3e14314027bb1d89cf7d59a06c
从{|}与
R0lGODlhEAAQAPMAMcDAwP/crv/erbigfVdLOyslHQAAAAECAwECAwECAwECAwECAwECAwECAwEC
AwECAyH/C01TT0ZGSUNFOS4wGAAAAAxtc09QTVNPRkZJQ0U5LjAHgfNAGQAh/wtNU09GRklDRTku
MBUAAAAJcEhZcwAACxMAAAsTAQCanBgAIf8LTVNPRkZJQ0U5LjATAAAAB3RJTUUH1AkWBTYSQXe8
fQAh+QQBAAAAACwAAAAAEAAQAAADSQhgpv7OlDGYstCIMqsZAXYJJEdRQRWRrHk2I9t28CLfX63d
ZEXovJ7htwr6dIQB7/hgJGXMzFApOBYgl6n1il0Mv5xuhBEGJAAAOw==
此示例XML文件显然已经被修整为简洁/简单。每张纸币实际可能包含> 1图像,因此需要获得/匹配散列。
XML文件:
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE en-export SYSTEM "http://xml.evernote.com/pub/evernote-export.dtd">
<en-export export-date="20091029T063411Z" application="Evernote/Windows" version="3.0">
<note>
<title>A title here</title>
<content><![CDATA[
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE en-note SYSTEM "http://xml.evernote.com/pub/enml.dtd">
<en-note bgcolor="#FFFFFF">
<p>Some text here (followed by the picture)
<p><en-media hash="4aaafc3e14314027bb1d89cf7d59a06c" type="image/gif" border="0" width="16" height="16" alt="A picture"/></p>
<p>Some more text here (preceded by the picture)
</en-note>
]]></content>
<created>20090925T063154Z</created>
<note-attributes>
<author/>
</note-attributes>
<resource>
<data encoding="base64">
R0lGODlhEAAQAPMAMcDAwP/crv/erbigfVdLOyslHQAAAAECAwECAwECAwECAwECAwECAwECAwEC
AwECAyH/C01TT0ZGSUNFOS4wGAAAAAxtc09QTVNPRkZJQ0U5LjAHgfNAGQAh/wtNU09GRklDRTku
MBUAAAAJcEhZcwAACxMAAAsTAQCanBgAIf8LTVNPRkZJQ0U5LjATAAAAB3RJTUUH1AkWBTYSQXe8
fQAh+QQBAAAAACwAAAAAEAAQAAADSQhgpv7OlDGYstCIMqsZAXYJJEdRQRWRrHk2I9t28CLfX63d
ZEXovJ7htwr6dIQB7/hgJGXMzFApOBYgl6n1il0Mv5xuhBEGJAAAOw==
</data>
<mime>image/gif</mime>
<resource-attributes>
<file-name>clip_image001.gif</file-name>
</resource-attributes>
</resource>
</note>
</en-export>
实施的解决方案
使用Jackem建议的解决方案的概念。主要区别是我避免创建自己的Java类(并创建额外的依赖关系)。我做处理XSLT中,因为它是直截了当不够,仅参考附带的基本Java库外部依赖。
Jackem的解决方案是更正确因为它不输于一些哈希前导零,但是我发现,它借此在其他地方使用li'l基本两轮牛车的照顾容易得多。
<xsl:stylesheet version="2.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
...
xmlns:md5="java.security.MessageDigest"
xmlns:bigint="java.math.BigInteger"
exclude-result-prefixes="md5 bigint">
...
<xsl:for-each select="resource">
<xsl:variable name="md5inst" select="md5:getInstance('MD5')" />
<xsl:value-of select="md5:update($md5inst, $b64bin)" />
<xsl:variable name="imgmd5bytes" select="md5:digest($md5inst)" />
<xsl:variable name="imgmd5bigint" select="bigint:new(1, $imgmd5bytes)" />
<xsl:variable name="imgmd5str" select="bigint:toString($imgmd5bigint, 16)" />
<!-- NOTE: $imgmd5str loses the leading zero from imgmd5bytes (if there is one) -->
</xsl:for-each>
...
P.S.看到sibling question我实施base64-->image file
转换
这个问题是一个 another question I have asked previously subquestion。
谢谢!我设法使用这个相同的概念来实现它,除了我自己不创建类,而只是从XSLT中调用这些方法。我会发布我的impl。很快就会解决... – bguiz 2009-11-07 23:39:33
Credit to credit due:Java代码是根据不同的答案改编的问题http://stackoverflow.com/questions/332079/in-java-how-do-i-convert-a-byte-阵列到一个串 - 的 - 己数字-而维持乐 – 2009-11-08 16:04:07