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我使用以下查询从mysql表中检索信息。将MySQL查询转换为Informix
SELECT ACCESS_TOKEN,
AUTHZ_USER,
TOKEN_SCOPE,
TOKEN_STATE,
REFRESH_TOKEN_TIME_CREATED,
REFRESH_TOKEN_VALIDITY_PERIOD,
IDN_OAUTH2_ACCESS_TOKEN_SELECTED.TOKEN_ID
FROM
(SELECT ACCESS_TOKEN,
AUTHZ_USER,
TOKEN_STATE,
REFRESH_TOKEN_TIME_CREATED,
REFRESH_TOKEN_VALIDITY_PERIOD,
TOKEN_ID
FROM IDN_OAUTH2_ACCESS_TOKEN
WHERE CONSUMER_KEY = ""
AND REFRESH_TOKEN = ""
ORDER BY TIME_CREATED DESC
LIMIT 1) AS IDN_OAUTH2_ACCESS_TOKEN_SELECTED
JOIN IDN_OAUTH2_SCOPE_ASSOCIATION
WHERE IDN_OAUTH2_ACCESS_TOKEN_SELECTED.TOKEN_ID =
IDN_OAUTH2_SCOPE_ASSOCIATION.TOKEN_ID;
如何在具有相同表的Informix数据库中获得相同的结果?
ANSI SQL需要对每个JOIN,但在这里,你有一个相反。只要将最后的WHERE更改为ON即可。 – jarlh
它的工作,添加了一个答案。 –