0
function roll(){
randomNumber = Math.ceil(Math.random() * range);
randomNumber2 = Math.ceil(Math.random() * range);
randomNumber3 = Math.ceil(Math.random() * range);
dice1_mc.gotoAndStop(randomNumber);
dice2_mc.gotoAndStop(randomNumber2);
dice3_mc.gotoAndStop(randomNumber3);
num1 = int(randomNumber);
num2 = int(randomNumber2);
num3 = int(randomNumber3);
trace(num1);
trace(num2);
trace(num3)
}
function AddCheck(e:MouseEvent):void {
ans = num1+num2+num3;
if (displayText.text == String(ans)){
//score++;
trace("Correct");
trace(ans);
displayText.text ="";
score+=1;
displayScore.text = String(score);
opsymbol=0;
RandomizeOperation();
}else{
trace("answer is " + ans + "------")
clearTxt();
//RandomizeOperation()
}
}
function MultiCheck(e:MouseEvent):void {
ans = num1*num3;
if (displayText.text == String(ans)){
//score++;
trace("Correct");
displayText.text ="";
score+=1;
displayScore.text = String(score);
opsymbol=0;
RandomizeOperation();
}else{
trace("answer is " + ans + "------")
clearTxt();
//RandomizeOperation()
}
}
function SubCheck(e:MouseEvent):void {
ans = num1-num2-num3;
if (displayText.text == String(ans)){
//score++;
trace("Correct");
trace(ans);
displayText.text ="";
score+=1;
opsymbol=0;
displayScore.text = String(score);
RandomizeOperation();
}else{
trace("answer is " + ans + "------")
clearTxt();
//RandomizeOperation()
}
}
function RandomizeOperation(){
var oprange:uint = 2;
opsymbol = Math.ceil(Math.random() * oprange);
//opsymbol = 2;
//trace(opsymbol);
if(opsymbol == 1){
dice2_mc.visible= true;
trace(opsymbol + " addition");
enterAns_btn.addEventListener(MouseEvent.CLICK, AddCheck);
roll();
}
if(opsymbol == 2){
dice2_mc.visible= true;
trace(opsymbol + " subtraction");
enterAns_btn.addEventListener(MouseEvent.CLICK, SubCheck);
roll();
}
}
在每次的问题改变操作矣。我不知道什么是错的。
示例第一个问题是1 + 2 + 3(它是6),下一个问题是减法(3-3-1-正确答案应该是-1),但是它会增加。我无法弄清楚什么是错的
先生,我能做些什么来解决这个问题?非常感谢。我不熟悉enterAns_btn.removeEventListener(event.type,arguments.callee); – Lemon 2014-12-07 16:31:43
在你的函数RandomizeOperation()中找到'if(opsymbol == 2)'部分并再次查看答案。你把它放在'enterAns_btn.addEventListener(MouseEvent.CLICK,SubCheck);'之前。它不需要任何编辑,对于这种情况来说,这是一个通用的命令,用于取消任何其他已有的侦听器。 – 2014-12-07 17:01:03
有没有什么办法可以比较我的答案,而不必通过第一次检查? – Lemon 2014-12-08 03:55:53