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我试图将ASCII转换为十六进制。这是我的功能。ascii到十六进制函数编译xcode但不是他的
NSString *asciiToHex(NSString *input) {
NSUInteger inputLength = [input length];
unichar *chars = malloc(inputLength * sizeof(unichar));
[input getCharacters:chars];
NSMutableString *hexString = [[NSMutableString alloc] init];
for (NSUInteger i = 0; i < inputLength; i++) {
[hexString appendFormat:@"%02x", chars[i]];
}
return hexString;
}
它工作在Xcode的,但如果我尝试编译它在狄奥项目中,我得到这个错误
error: cannot initialize a variable of type 'UInt8 *'
(aka 'unsigned char *') with an rvalue of type 'void *'
UInt8 *outBytes = malloc(sizeof(UInt8) * ((inLength/2) + 1));
^
我怎样才能获得THEOS编译它还是我如何重写功能?