SELECT stat.bug_num,
stat.build_id
FROM bug_status stat
WHERE stat.build_id = 3
OR stat.closed_to IN
(SELECT stat2.bug_num
FROM bug_status stat2
WHERE stat2.build_id = 3
)
;
(也有可能与JOIN要做到这一点,或与JOIN和UNION,但我相信上面是最直观的方式。)
编辑补充:这里是一个MySQL转录物证实以上:
mysql> create table bug_status
-> (bug_num numeric, build_id numeric, closed_to numeric);
Query OK, 0 rows affected (0.01 sec)
mysql> insert into bug_status values (1, 3, null);
Query OK, 1 row affected (0.00 sec)
mysql> insert into bug_status values (2, 4, null);
Query OK, 1 row affected (0.01 sec)
mysql> insert into bug_status values (3, null, 1);
Query OK, 1 row affected (0.00 sec)
mysql> insert into bug_status values (4, 3, null);
Query OK, 1 row affected (0.00 sec)
mysql> insert into bug_status values (5, null, 2);
Query OK, 1 row affected (0.00 sec)
mysql> SELECT stat.bug_num,
-> stat.build_id
-> FROM bug_status stat
-> WHERE stat.build_id = 3
-> OR stat.closed_to IN
-> (SELECT stat2.bug_num
-> FROM bug_status stat2
-> WHERE stat2.build_id = 3
-> )
-> ;
+---------+----------+
| bug_num | build_id |
+---------+----------+
| 1 | 3 |
| 3 | NULL |
| 4 | 3 |
+---------+----------+
3 rows in set (0.00 sec)
编辑补充,因为IN (...)
的做法似乎并没有在OP的版本的MySQL的工作:下面是给出了同样结果的替代查询:
SELECT stat.bug_num,
stat.build_id
FROM bug_status stat
LEFT
OUTER
JOIN bug_status stat2
ON stat.closed_to = stat2.bug_num
WHERE stat.build_id = 3
OR stat2.build_id = 3
;
要澄清,“关闭”不是构建ID,它是一个错误号。 – pennstatephil