Mysql的连接两个表获得基于条件

表一

id email firstname lastname 
1 [email protected] xx   xx  
2 [email protected] xb   ab

表B

id  email firstname lastname 
    1  [email protected] sd   cx  
    2  [email protected] df   dr

我想喜欢这个

email  firstname  lastname 

    [email protected]  xx   xx 
    [email protected]  xb   ab 
    [email protected]  df   dr

任何人请帮助我。我试过工会，明显没有得到我的结果

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2016-01-20 srivathi

在你的表中，有名字和姓氏的不同值电子邮件地址为[email protected]。不应该纠正？ –

向我们展示您已经测试 – bdn02

的表名和姓氏不同的select union。 – srivathi

你可以试试这个： -

SELECT email, firstname, lastname 
FROM table_a 
UNION 
SELECT email, firstname, lastname 
FROM table_b 
WHERE email NOT IN (SELECT email FROM table_a)

来源

2016-01-20 10:51:06

你可以做

select email, firstname, lastname from a 
union all 
select email, firstname, lastname from b 
where email not in (select email from a)

来源

2016-01-20 11:01:32 Marcx

SELECT email 
    , firstname 
    , lastname 
    FROM table_a 
UNION 
SELECT b.email 
    , b.firstname 
    , b.lastname 
    FROM table_b b 
    LEFT 
    JOIN table_a a 
    ON a.email = b.email 
WHERE a.email IS NULL;

来源

2016-01-20 11:28:00 Strawberry

感谢大家，工作正常 – srivathi

Mysql的连接两个表获得基于条件

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