与oracle diff: how to compare two tables?相同，只不过在mysql中。比较mysql中两个表之间的差异
假设我有两张表格t1和t2，它们在布局上是相同的，但可能包含不同的数据。
什么是区分这两个表的最好方法？
更确切地说，我试图找出一个简单的SQL查询，告诉我，如果在T1从一个行的数据是从相应的行T2中的数据
看来我不同不能使用相交或减号。当我尝试
SELECT * FROM robot intersect SELECT * FROM tbd_robot
我得到一个错误代码：
[错误代码：1064，SQL状态：42000]你在你的SQL语法 有一个错误;检查对应于你的MySQL服务器版本 为正确的语法在1号线
附近使用“SELECT * FROM tbd_robot”我做得不对语法手册？如果没有，是否有另一个我可以使用的查询？
编辑：此外，我通过免费版本的DbVisualizer查询。不知道这可能是一个因素。
INTERSECT需要在MySQL效仿：
SELECT 'robot' AS `set`, r.*
FROM robot r
WHERE ROW(r.col1, r.col2, …) NOT IN
(
SELECT *
FROM tbd_robot
)
UNION ALL
SELECT 'tbd_robot' AS `set`, t.*
FROM tbd_robot t
WHERE ROW(t.col1, t.col2, …) NOT IN
(
SELECT *
FROM robot
)
编辑：添加'周围的话说：设置
您可以使用UNION手动构建交集。如果你在两个表中都有一些独特的字段，例如ID：
SELECT * FROM T1
WHERE ID NOT IN (SELECT ID FROM T2)
UNION
SELECT * FROM T2
WHERE ID NOT IN (SELECT ID FROM T1)
如果没有独特的价值，你仍然可以扩展上面的代码来检查所有领域，而不是仅仅的ID，和使用，将它们连接（如ID NOT IN（。 ..）和OTHER_FIELD NOT IN（...）等）
真棒的答案。 – 2012-06-08 01:58:56
优雅的解决方案，@Roee Adler！ – Chubaka 2016-10-17 23:31:19
谢谢。这是行得通的。 – 2017-08-16 10:39:14
我发现基于海姆的回答在这个link
SELECT MIN (tbl_name) AS tbl_name, PK, column_list
FROM
(
SELECT ' source_table ' as tbl_name, S.PK, S.column_list
FROM source_table AS S
UNION ALL
SELECT 'destination_table' as tbl_name, D.PK, D.column_list
FROM destination_table AS D
) AS alias_table
GROUP BY PK, column_list
HAVING COUNT(*) = 1
ORDER BY PK
另一种解决方案，我创建一个PHP代码测试和显示所有两个数据库之间的差异。 如果在源数据库或测试数据库中存在表格，这也会显示。 你必须改变你的细节<>变量内容。
<?php
$User = "<DatabaseUser>";
$Pass = "<DatabasePassword>";
$SourceDB = "<SourceDatabase>";
$TestDB = "<DatabaseToTest>";
$link = new mysqli("p:". "localhost", $User, $Pass, "");
if (mysqli_connect_error()) {
die('Connect Error ('. mysqli_connect_errno() .') '. mysqli_connect_error());
}
mysqli_set_charset($link, "utf8");
mb_language("uni");
mb_internal_encoding("UTF-8");
$sQuery = 'SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA="'. $SourceDB .'";';
$SourceDB_Content = query($link, $sQuery);
if (!is_array($SourceDB_Content)) {
echo "Table $SourceDB cannot be accessed";
exit(0);
}
$sQuery = 'SELECT TABLE_NAME FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_SCHEMA="'. $TestDB .'";';
$TestDB_Content = query($link, $sQuery);
if (!is_array($TestDB_Content)) {
echo "Table $TestDB cannot be accessed";
exit(0);
}
$SourceDB_Tables = array();
foreach($SourceDB_Content as $item) {
$SourceDB_Tables[] = $item["TABLE_NAME"];
}
$TestDB_Tables = array();
foreach($TestDB_Content as $item) {
$TestDB_Tables[] = $item["TABLE_NAME"];
}
//var_dump($SourceDB_Tables, $TestDB_Tables);
$LookupTables = array_merge($SourceDB_Tables, $TestDB_Tables);
$NoOfDiscrepancies = 0;
echo "
<table border='1' width='100%'>
<tr>
<td>Table</td>
<td>Found in $SourceDB (". count($SourceDB_Tables) .")</td>
<td>Found in $TestDB (". count($TestDB_Tables) .")</td>
<td>Test result</td>
<tr>
";
foreach($LookupTables as $table) {
$FoundInSourceDB = in_array($table, $SourceDB_Tables) ? 1 : 0;
$FoundInTestDB = in_array($table, $TestDB_Tables) ? 1 : 0;
echo "
<tr>
<td>$table</td>
<td><input type='checkbox' ". ($FoundInSourceDB == 1 ? "checked" : "") ."></td>
<td><input type='checkbox' ". ($FoundInTestDB == 1 ? "checked" : "") ."></td>
<td>". compareTables($SourceDB, $TestDB, $table) ."</td>
</tr>
";
}
echo "
</table>
<br><br>
No of discrepancies found: $NoOfDiscrepancies
";
function query($link, $q) {
$result = mysqli_query($link, $q);
$errors = mysqli_error($link);
if ($errors > "") {
echo $errors;
exit(0);
}
if($result == false) return false;
else if ($result === true) return true;
else {
$rset = array();
while ($row = mysqli_fetch_assoc($result)) {
$rset[] = $row;
}
return $rset;
}
}
function compareTables($source, $test, $table) {
global $link;
global $NoOfDiscrepancies;
$sQuery = "
SELECT column_name,ordinal_position,data_type,column_type FROM
(
SELECT
column_name,ordinal_position,
data_type,column_type,COUNT(1) rowcount
FROM information_schema.columns
WHERE
(
(table_schema='$source' AND table_name='$table') OR
(table_schema='$test' AND table_name='$table')
)
AND table_name IN ('$table')
GROUP BY
column_name,ordinal_position,
data_type,column_type
HAVING COUNT(1)=1
) A;
";
$result = query($link, $sQuery);
$data = "";
if(is_array($result) && count($result) > 0) {
$NoOfDiscrepancies++;
$data = "<table><tr><td>column_name</td><td>ordinal_position</td><td>data_type</td><td>column_type</td></tr>";
foreach($result as $item) {
$data .= "<tr><td>". $item["column_name"] ."</td><td>". $item["ordinal_position"] ."</td><td>". $item["data_type"] ."</td><td>". $item["column_type"] ."</td></tr>";
}
$data .= "</table>";
return $data;
}
else {
return "Checked but no discrepancies found!";
}
}
?>
select t1.user_id,t2.user_id
from t1 left join t2 ON t1.user_id = t2.user_id
and t1.username=t2.username
and t1.first_name=t2.first_name
and t1.last_name=t2.last_name
尝试。这会比较你的表并找到所有匹配的对，如果有任何不匹配，则返回NULL。
真棒，谢谢！显然，我不需要“按部就班”的部分，但它现在的作品 – echoblaze 2009-06-04 13:38:54