MySQL查询通过

-3

我有this unanswered question在那里我有这个错误的结果查询得到，因为只有完全组的模式的错误结果：MySQL查询通过

SELECT 
    t1.patient_id, 
    CONVERT(aes_decrypt(t4.patient_name_en, :encKey) USING utf8mb4) as patient_name_en, 
    min(t3.date_of_visit) as date_of_visit, 
    t2.diagnosis_name, 
    max(ifnull(t5.date_of_assessment, 'N/A')) as date_of_assessment, 
    ifnull(t5.assessment_result, 0) as assessment_result 
FROM consultation t1 
LEFT JOIN diagnosis t2 
    ON t1.diagnosis_id = t2.diagnosis_id 
LEFT JOIN visit t3 
    ON t3.visit_id = t1.visit_id 
LEFT JOIN patient t4 
    ON t4.patient_id = t3.patient_id 
LEFT JOIN diabetes_assessment t5 
    ON t5.patient_id = t4.patient_id 
WHERE 
    t2.diagnosis_name LIKE :diagName AND 
    t1.clinic_id = :cid AND 
    t3.visit_status=:visit_status 
GROUP BY 
    t1.patient_id, 
    t2.diagnosis_name, 
    t3.date_of_visit 
    t4.patient_name_en, 
    t5.date_of_assessment 
    t5.assessment_result 
ORDER BY t5.date_of_assessment DESC

，给了我这样的结果：

新的事情是，我尝试使用子查询环路下面的查询通过patient_id：

SELECT t1.patient_id, 
    CONVERT(aes_decrypt(t4.patient_name_en, 'key1') USING utf8mb4) as patient_name_en, 
    min(t3.date_of_visit) as date_of_visit, 
    t2.diagnosis_name, 
    max(ifnull(t5.date_of_assessment, 'N/A')) as date_of_assessment, 
    ifnull(t5.assessment_result, 0) as assessment_result 
FROM consultation t1 
LEFT JOIN diagnosis t2 
    ON t1.diagnosis_id = t2.diagnosis_id 
LEFT JOIN visit t3 
    ON t3.visit_id = t1.visit_id 
LEFT JOIN patient t4 
    ON t4.patient_id = t3.patient_id 
LEFT JOIN diabetes_assessment t5 
    ON t5.patient_id = t4.patient_id 
WHERE t1.patient_id IN 
(SELECT t1.patient_id 
FROM consultation t1 
LEFT JOIN diagnosis t2 ON t1.diagnosis_id = t2.diagnosis_id 
LEFT JOIN visit t3 ON t3.visit_id = t1.visit_id 
LEFT JOIN patient t4 ON t4.patient_id = t3.patient_id 
LEFT JOIN diabetes_assessment t5 ON t5.patient_id = t4.patient_id 
WHERE t2.diagnosis_name LIKE '%Diabetes%' AND t1.clinic_id = '361' 
AND t3.visit_status="Active" 
GROUP BY t1.patient_id) AND 
t2.diagnosis_name LIKE '%Diabetes%' AND t1.clinic_id = '361' 
AND t3.visit_status="Active" 
GROUP BY t1.patient_id, t5.date_of_assessment, t4.patient_name_en, t3.date_of_visit, t2.diagnosis_name, t5.assessment_result 
ORDER BY t5.date_of_assessment DESC

而且我已经得到以高于图像显示同样的结果。

Here is the an sql fiddle about my problem

我真正想要的是仅显示以下两排它通过patient_id意味着组。