2017-09-02 91 views
1

而不是使用产品ID,我有一个从0开始的购物车中每个商品的索引。购物车中的每个商品都有自己的从购物车按钮中删除/删除。当用户点击该按钮时,该值通过AJAX发布到一个PHP脚本:商品不会从购物车中删除

if(isset($_POST['indexToRemove']) && $_POST['indexToRemove'] !== "") { 

     $key_to_remove = $_POST['indexToRemove']; 
     if(count($_SESSION['cart_array']) <=1) { 
      unset($_SESSION['cart_array']); 

     } else { 

      unset($_SESSION['cart_array'][$key_to_remove]); 

     } 
    } 

如果我CONSOLE.LOG上点击()indexToRemove,它显示在控制台中正确的值。但是,该项目永远不会从会话中删除,并且在控制台中没有错误来帮助进行故障排除。

这里是jQuery的:

$("body").on("click", ".removeItem", function() { 
     var indexToRemove = $(this).data('itr'); 
     var div = $(this).parents("div.hr"); 
     $.ajax({ 
      url: 'functions/show-cart.php', 
      type: 'POST', 
      dataType: 'json', 
      data: { 
       indexToRemove: indexToRemove 
      }, 
      beforeSend: function() { 
       $(div).html("<img src='images/spinner.gif'>"); 
       $("#total").empty(); 
      }, 
     }) 

     .done(function (data) { 
      $(div).fadeOut(); 
      show_cart(); 
     }) 

     .fail(function (jqXHR, textStatus, errorThrown) { 
      console.log(textStatus + ': ' + errorThrown); 
      console.warn(jqXHR.responseText); 
     }) 
    }) 

添加到购物车代码:

$quantity = 1; 
$product_id = $_POST['id']; 
$colour = $_POST['colour']; 
$size = $_POST['size']; 


    $key = "{$product_id}.{$colour}.{$size}"; 
    if (empty($_SESSION['cart_array'][$key])) { 
    $_SESSION['cart_array'][$key] = array(
     "item_id" => $product_id, 
     "quantity" => $quantity, 
     "colour" => $colour, 
     "size" => $size, 
    ); 
    } 
    else { 
     $_SESSION['cart_array'][$key]['quantity'] += $quantity; 
    } 

PHP代码用于显示购物车项目:

if(!isset($_SESSION['cart_array'])) { 

    $itemsInCart = 0; 
    $response['total'] = 0; 
    echo json_encode($response); 

} else { 

     $featured = "Yes"; 
     $i=0; 
     foreach($_SESSION['cart_array'] as $each_item) { 
      $item_id = $each_item['item_id']; 
      $colour = $each_item['colour']; 
      $size = $each_item['size']; 


     $stmt = $link->prepare("SELECT `product_name`, `price`, `pic_name` FROM `products` as `p` INNER JOIN `product_images` as `pi` ON p.`id` = pi.`product_id` WHERE p.`id` = ? AND `featured` = ?"); 
      $stmt->bind_param("is", $item_id, $featured); 
      $stmt->execute(); 
      $result = $stmt->get_result(); 
      $numRows = $result->num_rows; 
      if($numRows > 0) { 
       while($row = $result->fetch_assoc()) { 
        $product_name = sanitize($row['product_name']); 
        $price = sanitize(money_format('%.2n', $row['price'])); 
        $subtotal = money_format('%.2n', $each_item['quantity'] * $price); 
        $pic_name = $row['pic_name']; 
        $cartTotal = $subtotal + $cartTotal; 
        $quantity = $each_item['quantity']; 

        $cart_details[] = array(

        "product_name" => $product_name, 
        "price" => $price, 
        "subtotal" => $subtotal, 
        "pic_name" => $pic_name, 
        "each_item" => $quantity, 
        "item_id" =>$item_id, 
        "i" => $i, 
        "colour" => $colour, 
        "size" => $size, 


        ); 

        $i++; 
       } 
      } 

      $stmt->close(); 
     } 


    $response['total'] = $cartTotal; 
    $response['cart'] = $cart_details; 
    echo json_encode($response); 
} 

回答

0

在您的客户端,你需要更改此行:

data: { 
    indexToRemove: indexToRemove 
}, 

到:

data: JSON.stringify({indexToRemove: indexToRemove}), 

而是在服务器端的第一个问题是:

unset($_SESSION['cart_array']["$key_to_remove"]); 
          ^   ^

将其更改为:

unset($_SESSION['cart_array'][$key_to_remove]); 

第二个是(因为该项目是一个JSON您需要的对象json_decode):

$key_to_remove = $_POST['indexToRemove']; 

将其更改为:

$key_to_remove = json_decode($_POST['indexToRemove']); 
+0

如果我只有1项,然后它的工作原理和项目被删除 – user8463989

+0

我不知道如何检查你的要求。如果我console.log()出indexToRemove,第一个购物车项目的值为0,seance项目值为1,第三个项目值为2,依此类推 – user8463989

+0

@ user8463989对不起,您可以在PHP中转储$ key_to_remove的值,你的数组和测试密钥是否有效一样?原因是因为我看到** $ key =“{$ product_id}。{$ color}。{$ size}”; **并且我认为这不是一个数字。 – gaetanoM

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