如何将变量分配给对象名称？

Question

尝试了以下操作，其中“objectname”包含字符串名称，要在创建对象时进行分配。

for record in result: 
    objectname = 'Customer' + str(record[0]) 
    print objectname 
    customername = str(record[1]) 
    objectname = Customer(customername) 

如果客户是一类。

在我的测试，这个循环运行两次打印“对象名”为customer1表和顾客2，但创建2个对象，但对象被称为“对象名”（它覆盖每个循环），相对于2个唯一对象customer1表或顾客2 。

它根本不在变量中分配字符串（customer1,2），而是纯粹的变量名称。

我试图对象名称指定字符串，但给人的语法错误

当然这是一定要做所有的时间，感谢您的帮助提前。

Answer 1

而不是使用一个新的变量为每一位客户则可以将对象存储在一个Python字典：

d = dict() 

for record in result: 
    objectname = 'Customer' + str(record[0]) 
    customername = str(record[1]) 
    d[objectname] = Customer(customername) 

print d 

我只是could'nt帮助我的自我书面方式存储在字典对象的示例一些代码（比我想要做的更多）。这就像上瘾。无论如何，我不会使用对象进行这种工作。我可能会使用一个sqlite数据库（可以保存在内存中，如果你想）。但是这段代码告诉你（希望）你如何使用字典来保存客户数据对象：

# Initiate customer dictionary 
customers = dict() 

class Customer: 
    def __init__(self, fname, lname): 
     self.fname = fname 
     self.lname = lname 
     self.address = None 
     self.zip = None 
     self.state = None 
     self.city = None 
     self.phone = None 

    def add_address(self, address, zp, state, city): 
     self.address = address 
     self.zip = zp 
     self.state = state 
     self.city = city 

    def add_phone(self, number): 
     self.phone = number 


# Observe that these functions are not belonging to the class.  
def _print_layout(object): 
     print object.fname, object.lname 
     print '===========================' 
     print 'ADDRESS:' 
     print object.address 
     print object.zip 
     print object.state 
     print object.city 
     print '\nPHONE:' 
     print object.phone 
     print '\n' 

def print_customer(customer_name): 
    _print_layout(customers[customer_name]) 

def print_customers(): 
    for customer_name in customers.iterkeys(): 
     _print_layout(customers[customer_name]) 

if __name__ == '__main__': 
    # Add some customers to dictionary: 
    customers['Steve'] = Customer('Steve', 'Jobs') 
    customers['Niclas'] = Customer('Niclas', 'Nilsson') 
    # Add some more data 
    customers['Niclas'].add_address('Some road', '12312', 'WeDon\'tHaveStates', 'Hultsfred') 
    customers['Steve'].add_phone('123-543 234') 

    # Search one customer and print him 
    print 'Here are one customer searched:' 
    print 'ooooooooooooooooooooooooooooooo' 
    print_customer('Niclas') 

    # Print all the customers nicely 
    print '\n\nHere are all customers' 
    print 'oooooooooooooooooooooo' 
    print_customers() 

Answer 2

你需要的是一本字典：

customers = {} 
for record in result: 
    objectname = 'Customer' + str(record[0]) 
    customers[customername] = Customer(str(record[1])) #assignment to dictionary 

Answer 3

它一般是没有多大用处具有动态生成的变量名称。我肯定会建议是这样的Niclas'的答案，而不是，但如果你知道这是你想要的这里是你如何能做到这一点：

for record in result: 
    objectname = 'Customer' + str(record[0]) 
    print objectname 
    customername = str(record[1]) 
    exec '%s = Customer(%r)' % (customername, customername) 

这将导致变量Customer1和Customer2被添加到最里面的范围，酷似如果你执行了下面几行：

Customer1 = Customer('Customer1') 
Customer2 = Customer('Customer2') 

在做这种方式，你需要确保customername是valid Python identifier。