SQL Server - 对于XML路径（嵌套元素，多条记录）

Question

努力编写可以在XML中生成嵌套元素的查询。谁能帮

输入：

SELECT EmpName AS [Name], 
     EmpSalary  AS [WageAmount], 
    Add1 AS [Address1], 
    Add2 AS [Address2], 
    Mobile AS [Mobile] 
FROM Employee 
FOR XML PATH 

表数据（2条记录地址不同emoployee存在）

Conrad Jagger 12345 London UK 9191919191 
Conrad Jagger 12345 Coventry UK 9191919191 

预期输出：（这额外的信息作为嵌套元素）

<Employee> 
    <Name>Conrad</Name> 
    <WageAmount>10000</WageAmount> 
    <AdditionalInfo> 
     <PersonAddress> 
        <Address1>London</Address1> 
        <Address2>UK</Address2> 
       <Mobile>919191919191</Mobile> 
     </PersonAddress> 
     <PersonAddress> 
        <Address1>Coventry</Address1> --->Second address 
        <Address2>UK</Address2> 
       <Mobile>919191919191</Mobile> 
     </PersonAddress> 
    </AdditionalInfo> 
    </Employee> 

如果你有单条记录，我不知道该怎么办e这项工作为多个记录即时获取

SELECT EmpName AS [Name], 
     EmpSalary AS [WageAmount], 
     Add1 AS [AdditionalInfo/Address1], 
     Add2 AS [AdditionalInfo/Address2], 
     Mobile AS [AdditionalInfo/Mobile] 
FROM Employee 
FOR XML PATH ('Employee') 

Answer 1

我希望有一个uniqe id列在表中。由于您尚未提供该列，因此我将加入EmpName列作为例子。

试试这个

SELECT EmpName AS [Name], 
     EmpSalary AS [WageAmount], 
     (SELECT 
     Add1 AS [PersonAddress/Address1], 
     Add2 AS [PersonAddress/Address2], 
     Mobile AS [PersonAddress/Mobile] FROM Employee B WHERE EmpName = A.EmpName 
     FOR XML PATH('AdditionalInfo'),type) 
FROM Employee A 
GROUP BY EmpName,EmpSalary 
FOR XML PATH ('Employee')