排序两个列表通过他们的第一个元素，压缩他们在斯卡拉

Question

val descrList = cursorReal.interfaceInfo.interfaces.map { 
    case values => (values.ifIndex , values.ifName , values.ifType) 
    } 

val ipAddressList = cursorReal.interfaceIpAndIndex.filter(x=> (!x.ifIpAddress.equalsIgnoreCase("0"))).map { 
    case values => (values.ifIndex,values.ifIpAddress) 
    } 

例如，

val descrList = 
    List((12,"VoIP-Null0",1), (8,"FastEthernet6",6), (19,"Vlan11",53), 
     (4,"FastEthernet2",6), (15,"Vlan1",53), (11,"GigabitEthernet0",6), 
     (9,"FastEthernet7",6), (22,"Vlan20",53), (13,"Wlan-GigabitEthernet0",6), 
     (16,"Async1",1), (5,"FastEthernet3",6), (10,"FastEthernet8",6), 
     (21,"Vlan12",53), (6,"FastEthernet4",6), (1,"wlan-ap0",24), 
     (17,"Virtual-Template1",131), (14,"Null0",1), (20,"Vlan10",53), 
     (2,"FastEthernet0",6), (18,"NVI0",1), (7,"FastEthernet5",6), 
     (29,"Virtual-Access7",131), (3,"FastEthernet1",6), (28,"Virtual-Access6",131)) 

val ipAddressList = List((21,"192.168.12.1"), (19,"192.168.11.1"), 
         (11,"104.36.252.115"), (20,"192.168.10.1"), 
         (22,"192.168.20.1")) 

在这两个列表中第一个元素是指数，我必须明智合并这两个列表索引。这意味着 (21,"192.168.12.1")此ipAddress应与(21,"Vlan12",53)合并并形成如下(21,"Vlan12",53,"192.168.12.1")的新列表。

Answer 1

scala> descrList map {case (index, v1, v2) => 
    (index, v1, v2, ipAddressList.toMap.getOrElse(index, "empty"))} 
res0: List[(Int, String, Int, String)] = List(
(12,VoIP-Null0,1,empty), (8,FastEthernet6,6,empty), (19,Vlan11,53,192.168.11.1), 
(4,FastEthernet2,6,empty), (15,Vlan1,53,empty), (11,GigabitEthernet0,6,104.36.252.115), 
(9,FastEthernet7,6,empty), (22,Vlan20,53,192.168.20.1), (13,Wlan-GigabitEthernet0,6,empty), 
(16,Async1,1,empty), (5,FastEthernet3,6,empty), (10,FastEthernet8,6,empty), 
(21,Vlan12,53,192.168.12.1), (6,FastEthernet4,6,empty), (1,wlan-ap0,24,empty), (17,Virtual- 
Template1,131,empty), (14,Null0,1,empty), (20,Vlan10,53,192.168.10.1), (2,FastEthernet0,6,empty), 
(18,NVI0,1,empty), (7,FastEthernet5,6,empty), (29,Virtual-Access7,131,empty), 
(3,FastEthernet1,6,empty), (28,Virtual-Access6,131,empty)) 

Answer 2

首先，我建议你生成一个Map而不是List。一个Map性质有一个索引器，在你的情况下，这将是ifIndex值。

一旦你有地图中的地方，可以使用这样的（样品从该其他SO Best way to merge two maps and sum the values of same key?）

从雷克斯克尔： MAP1 ++ map2.map {情况下（K，V）=>ķ - >（v + map1.getOrElse（k，0））}

或者像这样从Matthew Farwell： （map1.keySet ++ map2.keySet）.map（i =>（i，map1.getOrElse i，0）+ map2.getOrElse（i，0））}。toMap

如果你不能以任何理由使用Maps，那么查看一下你现有的项目库，如果你有Scalaz，那么哟你有一些可用的工具。

Scalaz：https://github.com/scalaz/scalaz

如果你有油滑的，你也有一些很好的工具来直接使用。

油滑：http://slick.typesafe.com/docs/

Answer 3

首先考虑转换decrList到Map，这样，

val a = (for ((k,v1,v2) <- descrList) yield k -> (v1,v2)).toMap 

然后，我们可以看一下键ipAddressList和结块元素融入到新的记录，如下，

for ((k,ip) <- ipAddressList ; v = a.getOrElse(k,("none","none"))) yield (k,v._1,v._2,ip) 

因此，对于ipAddressList，

res: List((21,Vlan12,53,192.168.12.1), (19,Vlan11,53,192.168.11.1), 
      (11,GigabitEthernet0,6,104.36.252.115), (20,Vlan10,53,192.168.10.1), 
      (22,Vlan20,53,192.168.20.1)) 

Answer 4

鉴于数据：

val descrList = 
    List((12, "VoIP-Null0", 1), (8, "FastEthernet6", 6), (19, "Vlan11", 53), 
    (4, "FastEthernet2", 6), (15, "Vlan1", 53), (11, "GigabitEthernet0", 6), 
    (9, "FastEthernet7", 6), (22, "Vlan20", 53), (13, "Wlan-GigabitEthernet0", 6), 
    (16, "Async1", 1), (5, "FastEthernet3", 6), (10, "FastEthernet8", 6), 
    (21, "Vlan12", 53), (6, "FastEthernet4", 6), (1, "wlan-ap0", 24), 
    (17, "Virtual-Template1", 131), (14, "Null0", 1), (20, "Vlan10", 53), 
    (2, "FastEthernet0", 6), (18, "NVI0", 1), (7, "FastEthernet5", 6), 
    (29, "Virtual-Access7", 131), (3, "FastEthernet1", 6), (28, "Virtual-Access6", 131)) 

val ipAddressList = List((21, "192.168.12.1"), (19, "192.168.11.1"), 
    (11, "104.36.252.115"), (20, "192.168.10.1"), 
    (22, "192.168.20.1")) 

合并和排序：

val addrMap = ipAddressList.toMap 

val output = descrList 
    .filter(x => addrMap.contains(x._1)) 
    .map(x => x match { case (i, a, b) => (i, a, b, addrMap(i)) }) 
    .sortBy(_._1) 

output foreach println 

输出：

(11,GigabitEthernet0,6,104.36.252.115) 
(19,Vlan11,53,192.168.11.1) 
(20,Vlan10,53,192.168.10.1) 
(21,Vlan12,53,192.168.12.1) 
(22,Vlan20,53,192.168.20.1)