如何使用ManyToMany字段填充默认表单数据？

Question

好的，我一直在爬行谷歌和Django文档超过2个小时（以及freenode上的IRC频道），并没有能够找出这一个。

基本上，我有一个名为Room模型，该模型显示如下：

class Room(models.Model): 
    """ 
    A `Partyline` room. Rooms on the `Partyline`s are like mini-chatrooms. Each 
    room has a variable amount of `Caller`s, and usually a moderator of some 
    sort. Each `Partyline` has many rooms, and it is common for `Caller`s to 
    join multiple rooms over the duration of their call. 
    """ 
    LIVE = 0 
    PRIVATE = 1 
    ONE_ON_ONE = 2 
    UNCENSORED = 3 
    BULLETIN_BOARD = 4 
    CHILL = 5 
    PHONE_BOOTH = 6 
    TYPE_CHOICES = (
     ('LR', 'Live Room'), 
     ('PR', 'Private Room'), 
     ('UR', 'Uncensored Room'), 
    ) 

    type = models.CharField('Room Type', max_length=2, choices=TYPE_CHOICES) 
    number = models.IntegerField('Room Number') 
    partyline = models.ForeignKey(Partyline) 
    owner = models.ForeignKey(User, blank=True, null=True) 
    bans = models.ManyToManyField(Caller, blank=True, null=True) 

    def __unicode__(self): 
     return "%s - %s %d" % (self.partyline.name, self.type, self.number) 

我也得到了它具有以下的ModelForm代表我Room模型forms.py：

from django.forms import ModelForm 

from partyline_portal.rooms.models import Room 


class RoomForm(ModelForm): 
    class Meta: 
     model = Room 

我创建的视图允许管理员编辑给定的Room对象。这是我的观点（迄今为止）：

def edit_room(request, id=None): 
    """ 
    Edit various attributes of a specific `Room`. Room owners do not have 
    access to this page. They cannot edit the attributes of the `Room`(s) that 
    they control. 
    """ 
    room = get_object_or_404(Room, id=id) 
    if not room.is_owner(request.user): 
     return HttpResponseForbidden('Forbidden.') 

    if is_user_type(request.user, ['admin']): 
     form_type = RoomForm 
    elif is_user_type(request.user, ['lm']): 
     form_type = LineManagerEditRoomForm 
    elif is_user_type(request.user, ['lo']): 
     form_type = LineOwnerEditRoomForm 

    if request.method == 'POST': 
     form = form_type(request.POST, instance=room) 
     if form.is_valid(): 
      if 'owner' in form.cleaned_data: 
       room.owner = form.cleaned_data['owner'] 

     room.save() 
    else: 
     defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} 
     if room.owner: 
      defaults['owner'] = room.owner.id 
     if room.bans: 
      defaults['bans'] = room.bans.all() ### this does not work properly! 

     form = form_type(defaults, instance=room) 

    variables = RequestContext(request, {'form': form, 'room': room}) 
    return render_to_response('portal/rooms/edit.html', variables) 

现在，这个视图在我查看页面时工作正常。它显示了所有的表单属性，并且所有的默认值都被填入（当用户进行GET时）......除了ManyToMany字段的“默认值”字段的默认值。

基本上，如果管理员点击要编辑的对象Room，他们所去的页面将显示除'禁止'之外的所有Room的默认值。无论我做什么，我都找不到让Django显示Room对象的当前“禁止用户”的方法。下面是需要改变（从视图）的代码行：

defaults = {'type': room.type, 'number': room.number, 'partyline': room.partyline.id} 
if room.owner: 
     defaults['owner'] = room.owner.id 
if room.bans: 
     defaults['bans'] = room.bans.all() ### this does not work properly! 

必须有一些其他的语法，我必须使用指定的“禁令”字段的默认值。我真的一直在拉我的头发，并肯定会感谢一些帮助。

谢谢！

UPDATE

lazerscience居然帮我找到了在他的评论一个解决方案。基本上，它的工作方式是如果你传递一个主键列表。为了使它工作，我不得不改变：

if room.bans: 
     defaults['bans'] = room.bans.all() ### this does not work properly! 

到

if room.bans: 
     defaults['bans'] = [b.pk for b in room.bans.all()] 

和BAM，它会立即开始工作（当我查看的页面，它会显示的Caller个可选列表，与已经禁止来电者已经强调（选择）

Answer 1

您可能需要使用“初始”：Django set default form values